计数员工考勤

Question

我想写一份声明中用于计算员工考勤和执行他们的id，name，他一直工作在过去3个月的天为1个月，2和3指望NewTimeAttendance重复id 。

我试图计算：

Select COUNT(employeeid) 
    from NewTimeAttendance 
where employeeid=1 and (month=1 or month = 2 or month = 3) 

这绝对是工作，但只是一名雇员。

的第二次尝试：

SELECT COUNT(NewEmployee.EmployeeID) 
    FROM NewEmployee INNER JOIN NewTimeAttendance 
    ON NewEmployee.EmployeeID = NewTimeAttendance.EmployeeID 
    and (month=1 or month =2 or month = 3) 

这是工作，但它计算所有的员工，我希望它执行的每个EmployeeId，EmployeeName和number of days作为新的记录。

最后一次尝试：（你看到的代码之前...这是错的..但我想）

for i in 0..27 loop 
    SELECT COUNT(NewEmployee.EmployeeID),NewEmployee.EmployeeId,EmployeeName 
    FROM NewEmployee INNER JOIN NewTimeAttendance 
     ON NewEmployee.EmployeeID(i) = NewTimeAttendance.EmployeeID 
     and (month=1 or month =2 or month = 3) 
end loop 

我真的需要帮助...在此先感谢。

Answer 1

你需要一个GROUP BY功能，请尝试：

SELECT COUNT(NewEmployee.EmployeeID), NewEmployee.EmployeeId,EmployeeName 
FROM NewEmployee INNER JOIN NewTimeAttendance 
    ON NewEmployee.EmployeeID = NewTimeAttendance.EmployeeID 
    and (month=1 or month =2 or month = 3) 
GROUP BY NewEmployee.EmployeeID, EmployeeName