STDDEV函数和条款

我正在使用Oracle。我有表所示：STDDEV函数和条款

Company Employee salary 
    A1  Jim  122000 
...

我想和其薪水超过2点标准差（〜> 95％）的员工数最高回报的公司。这里是我的代码

With Com_2Std as (
Select company-name, AVG(salary)+2*STDDEV(salary) as AboveS 
From works 
Group By company-name) 

Select company-name, count(employee-name) as ENumber 
From works 
Where ENumber=MAX(
Select count(a.employee-name) 
From works a, Com_2Std b 
Where a.company-name=b.company-name 
And a.salary>b.AboveS; 
Group by a.company-name) 
Group by company-name;

我有两个quesions：

（1）我无法访问Oracle今天不能对其进行测试。请问我的代码是否正确？（2）看起来相当复杂，有什么办法可以简化它吗？

来源

2015-02-05 user4441082

不，你不能这样使用MAX（）。我不愿意为你写一个Oracle版本，因为我不太熟悉它的某些语法特点。 – shawnt00 2015-02-05 22:05:08

with Com_2Std as (
    select company-name, AVG(salary)+2*STDDEV(salary) as AboveS 
    from works 
    group by company-name 
), 
CompanyCount as (
    select a.company-name, count(*) as CountAboveS 
    from 
     works a 
     inner join Com_2Std b on a.company-name=b.company-name 
    where 
     a.salary > b.AboveS 
    group by a.company-name 
) 
select company-name 
from CompanyCount 
where CountAboveS = (select max(CountAboveS) from CompanyCount)

这应该是接近的。它也会产生联系。

来源

2015-02-05 22:10:31 shawnt00

谢谢。这非常有帮助。 – user4441082 2015-02-05 22:14:06

STDDEV函数和条款

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