如何分配在Matplotlib表特定颜色的特定细胞？

Question

继pylab_examples，我在matplotlib创建了一个简单的2×细胞表。

代码：

# Prepare table 
columns = ('A', 'B', 'C', 'D', 'E') 
rows = ["A", "B"] 
cell_text = [["1", "1","1","1","1"], ["2","2","2","2","2"]] 
# Add a table at the bottom of the axes 
ax[4].axis('tight') 
ax[4].axis('off') 
the_table = ax[4].table(cellText=cell_text,colLabels=columns,loc='center') 

现在，我要的颜色单元格A1与color = "#56b5fd"和单元格A2与color = "#1ac3f5"。所有其他细胞应保持白色。 Matplotlib的table_demo.py以及this例如只告诉我如何应用彩色地图依赖于细胞中的值预先定义的颜色。

如何分配在Matplotlib生成表的具体颜色以特定细胞？

Answer 1

上色在表格单元格的背景最简单的方法是使用cellColours参数。您可以提供与数据形状相同的列表或阵列列表。

import matplotlib.pyplot as plt 
# Prepare table 
columns = ('A', 'B', 'C', 'D', 'E') 
rows = ["A", "B"] 
cell_text = [["1", "1","1","1","1"], ["2","2","2","2","2"]] 
# Add a table at the bottom of the axes 
colors = [["#56b5fd","w","w","w","w"],[ "#1ac3f5","w","w","w","w"]] 

fig, ax = plt.subplots() 
ax.axis('tight') 
ax.axis('off') 
the_table = ax.table(cellText=cell_text,cellColours=colors, 
        colLabels=columns,loc='center') 

plt.show() 

替代地，可以设置一个特定小区的facecolor作为

the_table._cells[(1, 0)].set_facecolor("#56b5fd") 
the_table._cells[(2, 0)].set_facecolor("#1ac3f5") 

在相同的输出如上所得到的。