2014-09-20 196 views
-1

重要提示: 您只能从每个阵列中选择一个元素。动态获取阵列所有元素的所有组合

我正在写代码,让我测试测验排列。下面是我返回所有可能的排列数组的当前硬编码方式。我需要适应这是动态的,因为稍后会添加更多的数组。

我正在考虑一种方法,它可以接受一个选项数组,并返回一个排列数组,但是我的大脑在第一个循环后中断。任何帮助将非常感激。

options = 
[ 
    [["Geek", "Chef", "Supporter", "Fashionista"]], 
    [["0-1000", "1001-10000", "No limit"]], 
    [["Many", "For One"]] 
] 


def test_gifts(options) 
    options.each_with_index do |a,index| 
    .... 
    end 
end 

硬编码的:

character_types = ["Geek","Chef", "Supporter", "Fashionista"] 
price_ranges = ["0-1,000","1,001-10000","No limit"] 
party_size  = ["Many", "For One"] 


permutations = [] 
character_types.each do |type| 
    price_ranges.each do |price| 
    party_size.each do |party| 
     permutations << [type, price, party] 
    end  
    end 
end 

它返回

[["Geek", "0-1,000", "Many"], ["Geek", "0-1,000", "For One"], ["Geek", "1,001-10000", "Many"], ["Geek", "1,001-10000", "For One"], ["Geek", "No limit", "Many"], ["Geek", "No limit", "For One"], ["Chef", "0-1,000", "Many"], ["Chef", "0-1,000", "For One"], ["Chef", "1,001-10000", "Many"], ["Chef", "1,001-10000", "For One"], ["Chef", "No limit", "Many"], ["Chef", "No limit", "For One"], ["Supporter", "0-1,000", "Many"], ["Supporter", "0-1,000", "For One"], ["Supporter", "1,001-10000", "Many"], ["Supporter", "1,001-10000", "For One"], ["Supporter", "No limit", "Many"], ["Supporter", "No limit", "For One"], ["Fashionista", "0-1,000", "Many"], ["Fashionista", "0-1,000", "For One"], ["Fashionista", "1,001-10000", "Many"], ["Fashionista", "1,001-10000", "For One"], ["Fashionista", "No limit", "Many"], ["Fashionista", "No limit", "For One"]] 

回答

3

使用Array#product方法是:

character_types.product(price_ranges, party_size) 

处理未知数量的其他阵列:

arrays_to_permute = [character_types, price_ranges, party_size] 
first_array, *rest_of_arrays = arrays_to_permute 
first_array.product(*rest_of_arrays) 
+0

我会很快接受,谢谢,知道有东西在那里。 – jahrichie 2014-09-20 22:04:42

+0

我认为你的意思是'产品',你有'排列'。 (当你看到它时,我会删除这条评论。) – 2014-09-21 00:09:06

+0

你也可以这样做:'arrays_to_permute.delete.product(* arrays_to_permute)'。最好不要在变量名中包含'permute',因为这不涉及置换。组合,是的;排列,没有。 – 2014-09-21 00:11:20