Python - Regexp - 查找函数名称，但不是函数调用

Question

好吧，所以我有一堆C和C++代码，我需要通过筛选并找到函数defenitions。我不知道函数类型/返回值，我不知道函数defenition或函数调用中的参数数量等。

到目前为止，我有：

import re, sys 
from os.path import abspath 
from os import walk 

function = 'msg' 
regexp = r"(" + function + ".*[^;]){" 

found = False 
for root, folders, files in walk('C:\\codepath\\'): 
    for filename in files: 
     with open(abspath(root + '/' + filename)) as fh: 
      data = fh.read() 
      result = re.findall(regexp, data) 
      if len(result) > 0: 
       sys.stdout.write('\n Found function "' + config.function + '" in ' + filename + ':\n\t' + str(result)) 
       sys.stdout.flush() 
    break 

然而，这会产生一些不想要的结果。 的正则表达式必须是故障taulrant例如这些组合：

查找中说的所有突变 “味精” defenition而不是 “MSG（）” 呼叫：

void 
shapex_msg (struct shaper *s) 
{ 
    msg (M_INFO, "Output Traffic Shaping initialized at %d bytes per second", 
     s->bytes_per_second); 
} 

或

void shapex_msg (struct shaper *s) 
{ 
    msg (M_INFO, "Output Traffic Shaping initialized at %d bytes per second", 
     s->bytes_per_second); 
} 

或

void shapex_msg (struct shaper *s) { 
    msg (M_INFO, "Output Traffic Shaping initialized at %d bytes per second", 
     s->bytes_per_second); 
} 

Answer 1

也许类似下面的正则表达式：

def make_regex(name): 
    return re.compile(r'\s*%s\s*\([^;)]*\)\s*\{' % re.escape(name)) 

测试你的例子：

>>> text = ''' 
... void 
... shapex_msg (struct shaper *s) 
... { 
... msg (M_INFO, "Output Traffic Shaping initialized at %d bytes per second", 
...  s->bytes_per_second); 
... } 
... 
... void shapex_msg (struct shaper *s) 
... { 
... msg (M_INFO, "Output Traffic Shaping initialized at %d bytes per second", 
...  s->bytes_per_second); 
... } 
... 
... void shapex_msg (struct shaper *s) { 
... msg (M_INFO, "Output Traffic Shaping initialized at %d bytes per second", 
...  s->bytes_per_second); 
... }''' 
>>> shapex_msg = make_regex_for_function('shapex_msg') 
>>> shapex_msg.findall(text) 
['\nshapex_msg (struct shaper *s)\n{', ' shapex_msg (struct shaper *s)\n{', ' shapex_msg (struct shaper *s) {'] 

它仅适用于多定义：

>>> shapex_msg.findall('''int 
     shapex_msg  (
int a, 
int b 
) 

     {''' 
['\n \tshapex_msg \t(\nint a,\nint b\n) \n\n\t{'] 

虽然，与函数调用：

>>> shapex_msg.findall('shapex_msg(1,2,3);') 
[] 

正如一个音符，你的正则表达式不起作用，因为.*是贪婪的，因此它不匹配正确的右括号。