2009-12-11 50 views
1

我有一个SQL服务器中存储MINIMUM_AMOUNT,MAXIMUM_AMOUNT和CURRENCY_ID的表。现在我想构建一个SQL查询,它将检查要插入的新值是否已存在于表中。例如:我的表是有如下Tricky如果存在SQL查询需要检查重叠的值

RANGE_ID MINIMUM_AMOUNT  MAXIMUM_AMOUNT CURRENCY_ID 
------------------------------------------------------------ 
1   3000     9000    3 
2   12000    17000    3 

现在,当用户插入一个新的记录,它不应该已经获得的值之间是2条

即:用户不应该能够进入这些值对

1) Min Amount : 4000 , Max Amount : 5000 ,Currency Id : 3 
     because this range already lies in the first record (RANGE_ID 1) 
    2) Min Amount : 8000 , Max Amount : 10000,Currency d : 3 
     because the minimum amount is already present in the range specified in first record (3000-9000) 
    3) Min Amount : 8000, Max Amount : 15000 , currency Id=3 
     because the minimum amount is already present in one range and the maximum amount is also present in another range 
    4) Min Amount : 2500 , Max Amount : 11000 ,Currency Id=3 
     because the this range overlaps with the data in first record 

用户应该能够使用不同的货币ID输入上述范围。

我在寻找一个If Exists查询来检查这个。

回答

2

看一看这个

DECLARE @Table TABLE(
     RANGE_ID INT, 
     MINIMUM_AMOUNT FLOAT, 
     MAXIMUM_AMOUNT FLOAT, 
     CURRENCY_ID INT 
) 

INSERT INTO @Table (RANGE_ID,MINIMUM_AMOUNT,MAXIMUM_AMOUNT,CURRENCY_ID) SELECT 1,3000,9000,3 
INSERT INTO @Table (RANGE_ID,MINIMUM_AMOUNT,MAXIMUM_AMOUNT,CURRENCY_ID) SELECT 2,12000,17000,3 

DECLARE @NewMin FLOAT, 
     @NewMax FLOAT, 
     @CurrencyID INT 

SELECT @NewMin = 4000, 
     @NewMax = 5000, 
     @CurrencyID = 3 

SELECT * 
FROM @Table 
WHERE CURRENCY_ID = @CurrencyID 
AND  NOT (MINIMUM_AMOUNT > @NewMax OR MAXIMUM_AMOUNT < @NewMin) 

这是检查

  • 完全重叠
  • 部分重叠
  • 内部重叠
0

我认为这将相反做到这一点:

IF EXISTS 
(
    SELECT * 
    FROM MinMaxTable mmt 
    WHERE (mmt.CURRENCY_ID = @currencyID) AND 
      (@minAmount BETWEEN mmt.MINIMUM_AMOUNT AND mmt.MAXIMUM_AMOUNT) AND 
      (@maxAmount BETWEEN mmt.MINIMUM_AMOUNT AND mmt.MAXIMUM_AMOUNT) 
) 
BEGIN 
    /* New data is within an existing range. */ 
END 
ELSE 
BEGIN 
    /* Partially or completely outside an existing range. */ 
END; 

使用IF NOT EXISTS来反转条件。

+0

这不处理的重叠检查重叠 – Shyju 2009-12-11 06:54:37

0
select 1 
from currency_ranges R 
where R.CURRENCY_ID = :newCurrency 
and (
(R.MINIMUM_AMOUNT <= :newMin and R.MAXIMUM_AMOUNT >= :newMin) 
or (R.MINIMUM_AMOUNT <= :newMax and R.MAXIMUM_AMOUNT >= :newMax) 
) 

这可以被用来作为一个EXISTS语句范围