4
这里是一个形象:SQL甲骨文继承关系数据库
这是我走了多远到编码:
CREATE TYPE appointment_list_type AS TABLE OF REF appointment_type;
/
CREATE OR REPLACE TYPE person_type AS OBJECT (
personID NUMBER,
Surname varchar2(10),
Forname varchar2(10),
dateOfBirth date,
AddressLine1 varchar2(30),
AddressLine2 varchar2(30),
Town varchar2(10),
contacTel1 varchar2(10),
contacTel2 varchar2(10)) NOT FINAL;
/
CREATE TYPE applicant_type UNDER person_type(
applicantID NUMBER,
maxPrice number(7,2),
desiredArea varchar2(10),
Attends appointment_list_type
);
/
CREATE TYPE salesperson_type UNDER person_type(
salespersonID NUMBER,
manager varchar2(10),
Makes appointment_list_type
);
/
这是创造的人分隔条件成的继承类型销售人员和申请人。
CREATE TYPE appointment_type AS OBJECT(
appointmentID NUMBER,
Appdate date,
Apptime timestamp,
appointmentType varchar2(10),
levelOfInterest varchar2(10),
offerMade varchar2(10),
Made_by REF salesperson_type,
Attends_by REF applicant_type
);
/
这是预约型,参考文献将它们联系在一起。
对于创建表:
CREATE TABLE person_table OF person_type (
personID PRIMARY KEY NOT NULL)
NESTED TABLE Attends STORE AS attend_meeting_table;
CREATE TABLE applicant_table OF applicant_type (
personID PRIMARY KEY NOT NULL)
NESTED TABLE Attends STORE AS attend_meeting_table;
CREATE TABLE salesperson_table OF salesperson_type (
personID PRIMARY KEY NOT NULL)
NESTED TABLE Makes STORE AS makes_meeting_table;
CREATE TABLE appointment_table OF appointment_type (
appointmentID PRIMARY KEY NOT NULL,
SCOPE FOR (Made_by) IS person_table,
SCOPE FOR (Attends_by) IS person_table);
而且,这里是什么,我做了一些代码,我现在这里是我的问题:
如何与做1对多直接到预约的继承工作?
我真的很困惑这一点。任何人都可以帮助我如何做到这一点?
你不需要';'**和**的'/'在一个普通的SQL语句。事实上,两者在一起都很糟糕。有关详细信息,请参阅此处:http://stackoverflow.com/a/10207695/330315 –