我想刮英国广播公司足球结果网站,以获得球队,投篮,进球,卡牌和事件。我目前有3个团队数据传递到URL中。通过报废的数据循环并输出结果
我用Python写的脚本,并使用美丽的汤bs4
包。当输出结果到屏幕时,第一队将被打印,第一和第二队,然后是第一,第二和第三队。因此,第一支球队有效地打印了3次,当我试图让3支球队只有一次。
一旦我有这个问题排序,我会写结果到文件。我将团队数据添加到数据框中,然后添加到列表中(我不确定这是否是最好的方法)。 我确定如果是与for
循环有关,但我不确定如何解决问题。 代码:
from bs4 import BeautifulSoup
import urllib2
import pandas as pd
out_list = []
for numb in('EFBO839787', 'EFBO839786', 'EFBO815155'):
url = 'http://www.bbc.co.uk/sport/football/result/partial/' + numb + '?teamview=false'
teams_list = []
inner_page = urllib2.urlopen(url).read()
soupb = BeautifulSoup(inner_page, 'lxml')
for report in soupb.find_all('td', 'match-details'):
home_tag = report.find('span', class_='team-home')
home_team = home_tag and ''.join(home_tag.stripped_strings)
score_tag = report.find('span', class_='score')
score = score_tag and ''.join(score_tag.stripped_strings)
shots_tag = report.find('span', class_='shots-on-target')
shots = shots_tag and ''.join(shots_tag.stripped_strings)
away_tag = report.find('span', class_='team-away')
away_team = away_tag and ''.join(away_tag.stripped_strings)
df = pd.DataFrame({'away_team' : [away_team], 'home_team' : [home_team], 'score' : [score], })
out_list.append(df)
for shots in soupb.find_all('td', class_='shots'):
home_shots_tag = shots.find('span',class_='goal-count-home')
home_shots = home_shots_tag and ''.join(home_shots_tag.stripped_strings)
away_shots_tag = shots.find('span',class_='goal-count-away')
away_shots = away_shots_tag and ''.join(away_shots_tag.stripped_strings)
dfb = pd.DataFrame({'home_shots': [home_shots], 'away_shots' : [away_shots] })
out_list.append(dfb)
for incidents in soupb.find("table", class_="incidents-table").find("tbody").find_all("tr"):
home_inc_tag = incidents.find("td", class_="incident-player-home")
home_inc = home_inc_tag and ''.join(home_inc_tag.stripped_strings)
type_inc_goal_tag = incidents.find("td", "span", class_="incident-type goal")
type_inc_goal = type_inc_goal_tag and ''.join(type_inc_goal_tag.stripped_strings)
type_inc_tag = incidents.find("td", class_="incident-type")
type_inc = type_inc_tag and ''.join(type_inc_tag.stripped_strings)
time_inc_tag = incidents.find('td', class_='incident-time')
time_inc = time_inc_tag and ''.join(time_inc_tag.stripped_strings)
away_inc_tag = incidents.find('td', class_='incident-player-away')
away_inc = away_inc_tag and ''.join(away_inc_tag.stripped_strings)
df_incidents = pd.DataFrame({'home_player' : [home_inc],'event_type' : [type_inc_goal],'event_time': [time_inc],'away_player' : [away_inc]})
out_list.append(df_incidents)
print "end"
print out_list
我是新来的Python和堆栈溢出,格式化我的问题有什么建议也很有用。
在此先感谢!
您的缩进已关闭,因此循环无法正确对齐。请修复它。我还建议你阅读[PEP8](https://www.python.org/dev/peps/pep-0008/) – ffledgling
这看起来像一个打印问题,在什么样的缩进级别打印'out_list' ?它应该在*零*缩进处,一直在代码的左边。要么是,要么将out_list *移动到循环的最顶部,以便在每次迭代之后重新分配循环。 – ffledgling
谢谢@ffledgling这是问题,我是新的python,并不明白如何工作。谢谢 – paulg