通过嵌套数组循环测试并输出结果相同的结果

Question

嗨，我想知道是否有人能指出我对这个问题的正确方向，我只是不知道从哪里开始。

我有如下这种结构

Array ( 
    [0] => Array ([day_id] => 1 [plan_id] => 3 [day_num] => 1 [schedule_time] => 1300866720 [checkin_time] => [fine] =>) 
    [1] => Array ([day_id] => 2 [plan_id] => 3 [day_num] => 2 [schedule_time] => 1300953120 [checkin_time] => [fine] =>) 
    [2] => Array ([day_id] => 3 [plan_id] => 3 [day_num] => 3 [schedule_time] => 1301039520 [checkin_time] => [fine] =>) 
    [3] => Array ([day_id] => 4 [plan_id] => 3 [day_num] => 4 [schedule_time] => 1301125920 [checkin_time] => [fine] =>)) 

我希望能够做的是循环通过它测试“schedule_time”的特定时间的数组，如果它匹配整个数组保存到一个新的阵列。所以说阵列0和1匹配它会输出这样

Array ( 
     [0] => Array ([day_id] => 1 [plan_id] => 3 [day_num] => 1 [schedule_time] => 1300866720 [checkin_time] => [fine] =>) 
     [1] => Array ([day_id] => 2 [plan_id] => 3 [day_num] => 2 [schedule_time] => 1300953120 [checkin_time] => [fine] =>)) 

相同结构等

Answer 1

你基本上可以说一切了。您需要创建一个新的array和loop而不是现有的和check some condition。

$new_array = array(); 

foreach($array as $item) { 
    if($item['schedule_time'] > something) { 
     $new_array[] = $item; 
    } 
} 

我建议阅读文档。

Answer 2

$mySpecialTimeToMatch = 0; //whatever time you want to match 
$newArray = array(); 
foreach ($arrayScheduledTasks as $task) { 
    foreach ($task as $key => $data) { 
     if("schedule_time" == $key && $mySpecialTimeToMatch == $data) { 
      $newArray[] = $task; 
     } 
    } 
} 

print_r($newArray);