将表1中的行移动到表2（存档），并将表1中的数据保留过去7天

Question

表1具有包括创建日期的列。我想归档比过去7天更早的行，我希望将这些行移动到新的表格Table2中。 如何编写将更新归档数据到表2中的脚本，并且仅保留表1中过去7天的数据。谢谢！

Answer 1

我会倾向于做这样的事情：

declare @cutoff_datetime datetime; 
set @cutoff_datetime = dateadd(day, -7, getdate()); 

insert into table2 (. . .) 
    select . . . 
    from table1 
    where createdate < @cutoff_datetime; 

delete from table1 
    where createdate < @cutoff_datetime; 

这是交易在以下两种情况下的安全：

不更新 table1
• 行;和
• 用当前时间插入新行。

如果行可以被更新，你应该问另一个问题有更详细的规格你想要做什么。

Answer 2

这使用datadd()和datediff()来获取7天前的一天的开始，并从早于7天前的table1删除行;同时使用output将已删除的行插入table2。

insert into table2 (col1, col2, some_date) 
select d.col1, d.col2, d.some_date 
from (
    delete 
    from table1 
    output deleted.col1, deleted.col2, deleted.some_date 
    where some_date < dateadd(day, datediff(day, 0, getdate() -7), 0) 
) d (col1, col2, some_date) 

---

Rextester演示：http://rextester.com/DNK69844

create table table1 (col1 int not null identity(2,1), col2 varchar(32), some_date date); 
insert into table1 values ('Eight','20170429'),('Seven','20170430'),('Six','20170501'); 

create table table2 (col1 int not null, col2 varchar(32), some_date date); 
insert into table2 values (1,'Nine','20170428'); 

select tbl='table1', col1, col2, some_date=convert(char(10),some_date,120) from table1 
union all 
select tbl='table2', col1, col2, some_date=convert(char(10),some_date,120) from table2; 

insert into table2 (col1, col2, some_date) 
select d.col1, d.col2, d.some_date 
from (
    delete 
    from table1 
    output deleted.col1, deleted.col2, deleted.some_date 
    where some_date < dateadd(day, datediff(day, 0, getdate() -7), 0) 
) d (col1, col2, some_date); 


select tbl='table1', col1, col2, some_date=convert(char(10),some_date,120) from table1 
union all 
select tbl='table2', col1, col2, some_date=convert(char(10),some_date,120) from table2; 

回报（前）：

+--------+------+-------+------------+ 
| tbl | col1 | col2 | some_date | 
+--------+------+-------+------------+ 
| table1 | 2 | Eight | 2017-04-29 | 
| table1 | 3 | Seven | 2017-04-30 | 
| table1 | 4 | Six | 2017-05-01 | 
| table2 | 1 | Nine | 2017-04-28 | 
+--------+------+-------+------------+ 

返回（后）：

+--------+------+-------+------------+ 
| tbl | col1 | col2 | some_date | 
+--------+------+-------+------------+ 
| table1 | 3 | Seven | 2017-04-30 | 
| table1 | 4 | Six | 2017-05-01 | 
| table2 | 1 | Nine | 2017-04-28 | 
| table2 | 2 | Eight | 2017-04-29 | 
+--------+------+-------+------------+ 

Answer 3

- 创建临时表

CREATE TABLE #temp (PK_Col INT); -- Only to store the Primary Key values of deleted rows. 
GO 

- 将行到归档表格

INSERT INTO Archive.Table (PK_Col , created_date , OtherCols,.....) 
OUTPUT inserted.PK_Col INTO #Temp 
SELECT PK_Col , created_date , OtherCols,..... 
FROM Table1 
WHERE created_date < DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()-7), 0) 
GO 

- 现在删除归档数据

DELETE FROM t 
FROM Table1 t 
WHERE EXISTS (SELECT 1 from #temp t1 WHERE t1.PK_Col = t.PK_Col) 
GO