熊猫合并两个dataframes具有相同的结构

Question

假设我有两个dataframes：

x1 x2 x3 
y1 a1 a1 a1  
y2 b1 b1 b1  
y3 c1 c1 c1 

    x1 x2 x3 
y1 a2 a2 a2  
y2 b2 b2 b2  
y3 c2 c2 c2   

这是从同一个地方在得到以下数据框中每个元素的两个值的列表，最简单的方法原始数据框？

x1  x2  x3 
y1 [a1,a2] [a1,a2] [a1,a2]  
y2 [b1,b2] [b1,b2] [b1,b2]  
y3 [c1,c2] [c1,c2] [c1,c2] 

Answer 1

使用applymap

In [953]: df1.applymap(lambda x: [x]) + df2.applymap(lambda x: [x]) 
Out[953]: 
      x1  x2  x3 
y1 [a1, a2] [a1, a2] [a1, a2] 
y2 [b1, b2] [b1, b2] [b1, b2] 
y3 [c1, c2] [c1, c2] [c1, c2] 

Answer 2

一（出许多）可能的解决方案：

In [63]: d1.astype(str).add(',').add(d2.astype(str)).apply(lambda x: x.str.split(',')) 
Out[63]: 
      x1  x2  x3 
y1 [a1, a2] [a1, a2] [a1, a2] 
y2 [b1, b2] [b1, b2] [b1, b2] 
y3 [c1, c2] [c1, c2] [c1, c2]