TypeError对象不可迭代

Question

当我试图在我的Django模板中遍历一个变量时出现以下错误。有问题的变量是我的DetailView子类中指定的型号的相关对象：

类型错误在/ EN /申请/ 50771459778/

'Householdmember' 对象不是可迭代

这里是我models.py文件：

class Applicant(models.Model): 
    user    = models.ForeignKey(User, editable=False) 
    bank_card_number = models.CharField(_('Bank card number'),max_length=50, unique=True) 
    site_of_interview = models.IntegerField(_('Site of interview'), choices = SITE_CHOICES, default=TIRANA, blank=False) 
    housenumber  = models.CharField(_('House Number'),max_length=8) 
    address_line1  = models.CharField(_('Address line 1'),max_length=50) 
    address_line2  = models.CharField(_('Apt #'),max_length=50,blank=True) 
    municipality  = models.CharField(_('Municipality/commune'),max_length=25) 
    district   = models.CharField(_('District'),max_length=25,blank=True) 
    urban    = models.IntegerField(_('Area (urban/rural)'), choices = AREA_CHOICES, blank=False) 
    postal   = models.CharField(_('Postal code'),max_length=25,blank=True) 

class Householdmember(models.Model): 
    applicant   = models.ForeignKey(Applicant) 
    first_name  = models.CharField(_('First name'),max_length=50,blank=False) 
    middle_name  = models.CharField(_('Middle name'),max_length=50,blank=True) 
    last_name   = models.CharField(_('Last name'),max_length=50,blank=False) 
    national_id  = models.CharField(_('National ID'),max_length=50,blank=False, unique=True) 
    male    = models.IntegerField(_('Gender'), choices = GENDER_CHOICES, blank=False) 
    date_of_birth  = models.DateField() 
    rel_to_head  = models.IntegerField(_('Gender'), choices = RELTOHEAD_CHOICES, blank=False) 
    disability  = models.IntegerField(_('Is disabled?'), choices = YESNO_CHOICES, blank=False) 
    created_at  = models.DateTimeField(auto_now_add = True) 
    updated_at  = models.DateTimeField(auto_now = True) 

这里是我的urls.py文件：

class ListViewApplicants(ListView): 
    paginate_by = 100 
    def get_queryset(self): 
     return Applicant.objects.all() 

class DetailViewUnmask(DetailView): 
    def get_object(self): 
     return self.get_queryset().get(pk=mask_toggle(self.kwargs.get("pk_masked"))) 

urlpatterns = patterns('', 
    url(r'^$', 
     login_required(ListViewApplicants.as_view( 
          template_name='applicants/index.html', 
          #context_object_name='form', 
          )), 
     name='index'), 
    url(r'^(?P<pk_masked>\d+)/$', 
     login_required(DetailViewUnmask.as_view(model=Applicant, 
          template_name='applicants/detail.html' 
          )), 
     name='detail'), 

这里是我的模板的相关部分，detail.html：

<h2>Household members</h2> 
<table class="package_detail"> 
    <tr> 
     {% include "applicants/householdmember_heading_snippet.html" %} 
    </tr> 

    {% for householdmember in applicant.householdmember_set.all %} 
    <tr> 

     {% for field in householdmember %} 
      <td>{{ field }}</td> 
     {% endfor %} 
     <!-- 
     <td>{{ householdmember.first_name }}</td> 
     <td>{{ householdmember.middle_name }}</td> 
     <td>{{ householdmember.last_name }}</td> 
     <td>{{ householdmember.national_id }}</td> 
     <td>{{ householdmember.get_male_display }}</td> 
     <td>{{ householdmember.date_of_birth }}</td> 
     <td>{{ householdmember.get_rel_to_head_display }}</td> 
     <td>{{ householdmember.get_disability_display }}</td> 
     --> 
    </tr> 
    {% endfor %} 
</table> 

被注释掉的部分（即在<!-- -->标签之间的部分）工作，这导致我认为我应该能够迭代householdmember变量。但是当我尝试这样做时，它不起作用 - 我只是得到上面的TypeError。

我已经在搜索stackoverflow.com exentsively为答案，但我可以找到最接近的答案是这一个：django how to loop through the context object passed back by a generic detailview?，但它不能解决我的问题，我想因为我使用基于类的视图。

将不胜感激任何帮助。谢谢！

Answer 1

你不能通过模型​​实例。 我建议你使用你的评论代码。

如果你仍然想使用一个for循环，也许你可以添加以下代码：

class Householdmember(models.Model): 
    # all yuur fields... 

    def __iter__(self): 
     return return [field.value_to_string(self) for field in Householdmember._meta.fields] 

但是，没有人建议

这是更好的：

class Householdmember(models.Model): 
    # all yuur fields... 

    def __iter__(self): 
     return [ self.first_name, 
       self.middle_name, 
       self.last_name, 
       self.national_id, 
       self.get_male_display, 
       self.date_of_birth, 
       self.get_rel_to_head_display, 
       self.get_disability_display ] 

Answer 2

我设法解决这个问题这里是如何。我使用的信息从这里：Iterate over model instance field names and values in template

这是我加入到我的models.py文件：

def get_all_fields(self): 
    fields = [] 
    for f in self._meta.fields: 
     fname = f.name   
     # resolve picklists/choices, with get_xyz_display() function 
     get_choice = 'get_'+fname+'_display' 
     if hasattr(self, get_choice): 
      value = getattr(self, get_choice)() 
     else: 
      try : 
       value = getattr(self, fname) 
      except User.DoesNotExist: 
       value = None 

     # only display fields with values and skip some fields entirely 
     if f.editable and f.name not in ('id', 'created_at', 'updated_at', 'applicant'): 

      fields.append(
       { 
       'label':f.verbose_name, 
       'name':f.name, 
       'value':value, 
       } 
      ) 
    return fields 

，这里是我的detail.html文件弄成什么看起来像：

<table class="package_detail"> 
    <tr> 
     {% include "applicants/householdmember_heading_snippet.html" %} 
    </tr> 
    {% for householdmember in applicant.householdmember_set.all %} 
    <tr>  
    {% for field in householdmember.get_all_fields %} 
     <td>{{ field.value }}</td> 
    {% endfor %} 
    </tr> 
    {% endfor %} 
</table> 

这使所需的输出。