我正在编写node.js应用程序的任务管理器。这些应用程序在任意端口开启,所以,为了达到这些目标我想伪造他们的根在 这样的URL:Socket.io在代理服务器收到握手响应之前关闭[ECONNRESET]
http://domain.com/proxy/yourApplication
那么第三方可以使HTTP请求发送到他们的应用,但不知道在哪个端口运行。
然后我选择http-proxy:
var express = require('express')
, router = express.Router()
, Helper = require('../helper')
, launcher = require('../launcher')
, httpProxy = require('http-proxy')
, proxy = httpProxy.createProxyServer({ws: true});
并侦听在这条路线的代码...
// Proxy
router.use('/proxy/:name?', function(req, res) {
var app, reqPath, referer, proxyUrl;
// Capture the referer to proxy the request
// in case the path is not clear enaugh
if (req.get('referer') !== undefined) {
var aux = req.get('referer').split('/');
referer = aux[aux.indexOf('proxy') + 1]
}
// This block returns an app object
// with the port where it is running
app = launcher.getApp(req.params.name)
|| launcher.getApp(referer);
if (app) {
// Here app is running
// In case the path is /proxy/:name
// instead of /proxy/:name/ you need this block
req.url = (req.url === '/') ? '' : req.url;
reqPath = (referer !== undefined)
? '/' + req.params.name + req.url
: req.url;
req.url = reqPath.replace('/proxy/', '/');
req.url = req.url.replace('/' + app.name, '');
// This block of code actually pipes the request
// to the running app and pass it to the client
proxyUrl = req.protocol + '://localhost:' + app.port;
proxy.web(req, res, {
target: proxyUrl
});
// Some logging
console.log('req url: %s', req.url);
console.log('proxy url: %s', proxyUrl);
console.log('referer: %s', referer);
} else {
// Here app is not running
res.status(404).json("App not running");
}
});
它的工作原理只是大多数应用程序很好,但与插座打开应用时。它提示:
WebSocket connection to 'ws://localhost/proxy/xy-terminal/socket.io/1/websocket/gMqK_XRwZENuUibi4ekJ' failed: Connection closed before receiving a handshake response
在服务器控制台...
Trace: { [Error: socket hang up] code: 'ECONNRESET' }
at process.<anonymous> (/Users/jdario/Development/xy-dashboard/www:107:11)
at process.emit (events.js:107:17)
at process._fatalException (node.js:236:26)
at ProxyServer.emit (/Users/jdario/Development/xy-dashboard/node_modules/http-proxy/node_modules/eventemitter3/index.js:75:35)
at ClientRequest.proxyError (/Users/jdario/Development/xy-dashboard/node_modules/http-proxy/lib/http-proxy/passes/web-incoming.js:140:16)
at ClientRequest.emit (events.js:129:20)
at Socket.socketCloseListener (_http_client.js:247:9)
at Socket.emit (events.js:129:20)
at TCP.close (net.js:485:12)
由于它是伪造应用程序根目录的“代理”,我可能无法单独修改它们的源代码,它们应该按预期工作。在正确的端口打开它们(在这种情况下为3000)时,它们不会显示任何错误。
预先感谢您!
你知道一个webSocket连接是作为一个http请求启动的吗?然后它被升级到webSocket协议?因此,您的代理需要处理该问题,并需要一种方法来告知哪个应用是webSocket连接的目的地。 – jfriend00
是的!其实我相信这个错误可能在那里,但经过检查http-proxy的源代码后,我找不到。另外,我必须指出,第一次完成后的其他连接试验。第一个是在'/ proxy/appName /'和'完成'到达'/ proxy/appName'时的'pending'。 – jsdario