我有一个数组($ scope.names),它包含一些简单的对象,我正在使用一些函数来清除变音符的值。当我用控制台打印这个值时,它显示我确定。例如:'La 45 km nordvest deBucureşti'将是'La 45 km nordvest de Bucuresti'。AngularJS Filter效果不好
我正在应用此方法和另一个变量($ scope.searchText)使搜索兼容。再次,这很好。
问题是,即使我正在标准化两个变量的值,它的过滤器不起作用。如果我尝试搜索'Bucures',它不会显示包含干净词'Bucures'(原始单词'Bucureş')的对象...
我做错了什么?
完整的代码是在这里:http://plnkr.co/edit/D5WfiOGd5I3QfcNVdOmr?p=preview
角度脚本是:
var app = angular.module('myApp', []);
app.controller('namesCtrl', function($scope, $filter) {
$scope.names = [
{
"adresa": "Str. Calafatului nr. 10",
"latitudine": "44.1",
"localitatea": "GALICEA MARE",
"longitudine": "23.3",
},
{
"adresa": "bd. Elisabeta nr. 1",
"latitudine": "44.170901",
"localitatea": "CONSTANŢA",
"longitudine": "28.663195",
},
{
"POTLOGI": "La 45 km nord- vest de Bucureşti",
"latitudine": "44.564319",
"localitatea": "POTLOGI",
"longitudine": "25.588091",
}
]
$scope.searchText = "";
$scope.searchCleanText = "";
$scope.myFilter = function (items) {
for (var i = 0; i < items.length; i++) {
var boolChk = false;
angular.forEach(items[i], function (value, key) {
var cleanValue = removeDiacritics(value).toLowerCase();
if (boolChk === false) {
boolChk = cleanValue.includes($scope.searchCleanText);
}
console.log(value + ' ' + cleanValue.includes($scope.searchCleanText) + '\tboolChk = ' + boolChk);
return boolChk;
});
}
}
$scope.$watch('searchText', function() {
$scope.searchCleanText = removeDiacritics($scope.searchText).toLowerCase();
$scope.showItems = $filter('filter')($scope.names, $scope.searchText, $scope.myFilter($scope.names));
console.log($scope.showItems);
});
});
感谢您的帮助。它有效,但我发现现在有更好的方法。我必须使用'function(actual,expected)'来返回一个布尔值。 – Doro