总结与条件

Question

我有一个查询clausule SUM。我需要根据列的总和。

这可能吗？

有没有人有我看的例子？

我下面的代码：

SELECT 
PL_MAT AS 'Código', 
RA_NOME AS 'Nome', 
RJ_DESC AS 'Cargo', 
SUM(PL_HORAS) AS 'Atrasos' 
--SUM(PL_HORAS) AS 'Hora Extra' -- I need SUM this 
FROM SPL020 
INNER JOIN SP9020 ON PL_PD = P9_CODIGO AND SP9020.D_E_L_E_T_ <> '*' AND SPL020.D_E_L_E_T_ <> '*' 
INNER JOIN SRA020 ON RA_MAT = PL_MAT AND SRA020.D_E_L_E_T_ <> '*' AND RA_FILIAL = PL_FILIAL 
INNER JOIN SRJ020 ON RJ_FUNCAO = RA_CODFUNC 
WHERE PL_DATA BETWEEN '20120616' AND '20120715' 
AND P9_CODIGO IN ('011','421','013','409') 
--AND P9_CODIGO IN ('408','007','420','009','015','016','018') -- I need sum this 
AND RA_CODFUNC IN ('0408','1204','1233')--AUX COLETA C,MOTORISTA D,MOTORISTA CARRETEIRO 
AND RA_SITFOLH NOT IN ('D','A') 
AND PL_FILIAL = '05' 
GROUP BY PL_MAT,RA_NOME,RA_ADMISSA,RA_CODFUNC,RJ_DESC,P9_DESC, PL_HORAS, P9_CODIGO 
ORDER BY RA_NOME 

Answer 1

这样做：

sum(case when p9_codigo in ('408','007','420','009','015','016','018') then pl_horas else 0 end) as 'Hora Extra' 

如果你虽然PUT和P9_CODIGO IN（ '011'， '421'， '013'， '409'）在where子句中，上面的不会被过滤。

所以你需要以不同的方式去除它们。

我猜你会需要它想：

sum(case when p9_codigo in ('011','421','013','409') then PL_HORAS else 0 end) as 'Atrasos', 
sum(case when p9_codigo in ('408','007','420','009','015','016','018') then pl_horas else 0 end) as 'Hora Extra' 

，并从where子句中删除过滤器。

Answer 2

podésprobar ESTO：

选择诺姆，货物，总和（Hora_Extra）作为Hora_Extra 从（ SELECT PL_MAT AS 'Codigo'， RA_NOME AS '诺姆'， RJ_DESC AS '货物'， SUM（PL_HORAS）AS 'Atrasos'，

P9_CODIGO为 'Codigo'

FROM SPL020

INNER JOIN SP9020 ON PL_PD = P9_CODIGO

AND SP9020.D_E_L_E_T_ <> '*'

AND SPL020.D_E_L_E_T_ <> '*'

INNER JOIN SRA020 ON RA_MAT = PL_MAT AND SRA020。D_E_L_E_T_ <> '*'

AND RA_FILIAL = PL_FILIAL

INNER JOIN SRJ020 ON RJ_FUNCAO = RA_CODFUNC

WHERE PL_DATA BETWEEN '20120616' AND '20120715'

AND P9_CODIGO IN（ '011' ， '421'， '013'， '409'）

和RA_CODFUNC IN（ '0408'， '1204'， '1233'）

和RA_SITFOLH NOT IN（ 'd'， 'A'）

AND PL_FILIAL = '05'

GROUP BY PL_MAT，RA_NOME，RA_ADMISSA，RA_CODFUNC，RJ_DESC，P9_DESC，PL_HORAS，P9_CODIGO

）如KK

其中Codigo在（ '408'， '007'， '420'， '009'， '015'， '016'， '018'） 为了通过诺姆

UNOS提示： 没有使用颚化符号（C” ó“digo） No uses espacios en los campos（Horas Extras）

Saludos

Answer 3

Got it！ 谢谢大家

SELECT 
DISTINCT PL_MAT AS 'Código', 
RA_NOME AS 'Nome', 
RJ_DESC AS 'Cargo', 
SUM(CASE WHEN P9_CODIGO IN ('082','080','030','409') THEN PL_HORAS ELSE 0 END) AS 'Atrasos', 
SUM(CASE WHEN P9_CODIGO IN ('408','007','420','009','015','016','018') THEN PL_HORAS ELSE 0 END) AS 'Hora extra' 
--SUM(PL_HORAS) AS 'Hora Extra' -- I need SUM this 
FROM SPL020 
INNER JOIN SP9020 ON PL_PD = P9_CODIGO AND SP9020.D_E_L_E_T_ <> '*' AND SPL020.D_E_L_E_T_ <> '*' 
INNER JOIN SRA020 ON RA_MAT = PL_MAT AND SRA020.D_E_L_E_T_ <> '*' AND RA_FILIAL = PL_FILIAL 
INNER JOIN SRJ020 ON RJ_FUNCAO = RA_CODFUNC 
WHERE PL_DATA BETWEEN '20120616' AND '20120715' 
--AND P9_CODIGO IN ('011','421','013','409') 
--AND P9_CODIGO IN ('408','007','420','009','015','016','018') -- I need sum this 
AND RA_CODFUNC IN ('0408','1204','1233')--AUX COLETA C,MOTORISTA D,MOTORISTA CARRETEIRO 
AND RA_SITFOLH NOT IN ('D','A') 
AND PL_FILIAL = '05' 
AND RA_MAT = '000007' 
GROUP BY PL_MAT, RA_NOME, RJ_DESC