有关如何让这个接受多个客户的任何帮助,以及为什么它不是现在呢?谢谢!如何在TCP Python聊天服务器上拥有多个客户端?
另外,有什么我做错了这个代码?我一直在关注大多的Python 2个教程,因为我无法找到任何的Python 3.4
这里是我的服务器代码:
import socket
import time
import os
from threading import Thread
folderPath = "Chat Logs"
filePath = folderPath + "/" + str(time.strftime("%H-%M-%S_%d-%m-%Y")) + ".txt"
def clientHandler(c):
while True:
data = c.recv(1024)
if not data:
break
data = data.decode("UTF-8")
message = str(data[:data.index("§")])
nick = str(data[data.index("§")+1:])
print(nick + ": " + message)
saveChat(nick, message)
print(" Sending: " + data)
c.send(bytes(data, "UTF-8"))
c.close()
def saveChat(nick, message):
if not os.path.exists(folderPath):
os.makedirs(folderPath)
if not os.path.exists(filePath):
f = open(filePath, "a")
f.close()
f = open(filePath, "a")
f.write(nick + ": " + message + "\n")
f.close()
def Main():
host = str(socket.gethostbyname(socket.gethostname()))
port = 5000
print(host + ":" + str(port) + "\n")
Clients = int(input("Clients: "))
s = socket.socket()
s.bind((host, port))
s.listen(Clients)
for i in range(Clients):
c, addr = s.accept()
print("Connection from: " + str(addr))
Thread(target=clientHandler(c)).start()
s.close()
if __name__ == "__main__":
Main()
这里是我的客户端代码:
import socket
def Main():
print("Send 'q' to exit\n")
address = str(input("ip:port -> "))
nick = input("nick: ")
try:
if address.index(":") != 0:
host = address[:address.index(":")]
port = int(address[address.index(":")+1:])
except ValueError:
host = address
port = 5000
s = socket.socket()
s.connect((host, port))
message = input("-> ")
while message != "q":
s.send(bytes(message + "ยง" + nick, "UTF-8"))
data = s.recv(1024)
data = data.decode("UTF-8")
data2 = data
messageServer = str(data[:data.index("ยง")])
nickServer = str(data[data.index("ยง")+1:])
if not data == data2:
print(nickServer + ": " + messageServer)
message = input("-> ")
s.close()
if __name__ == "__main__":
Main()
我得到的错误'导入错误:没有模块名为“thread''尝试做进口的时候'start_new_thread' – artman41 2014-10-19 14:02:21
啊我看,看在这里,这可能会对此有所了解。 https://stackoverflow.com/questions/5568555/thread-vs-threading – Totem 2014-10-19 17:46:28
啊,谢谢你的信息@Totem – artman41 2014-10-21 10:10:30