我有一个查询,我已经用来确定什么时候石英工作。我试图设计一种方法来确定石英工作何时落后或陷入困境。问题在于作业时间间隔不同,因此我希望在确定作业何时中断时能够使用“大于X的标准偏差”逻辑。有没有办法在MySQL中做到这一点?这将主要是:解析时间差异并除以mysql
(previous_fire_time - next_fire_time)/一个时间间隔= X性偏差
select job_group, job_name,
from_unixtime(prev_fire_time/1000) prev,
from_unixtime(next_fire_time/1000) next,
sec_to_time((next_fire_time - prev_fire_time)/1000) diff
from qrtz_triggers;
+-----------+------------------------+--------------------------+--------------------------+----------------+
| job_group | job_name | prev | next | diff |
+-----------+------------------------+--------------------------+--------------------------+----------------+
| jon | media | 2016-02-25 15:50:30.0000 | 2016-02-25 16:50:30.0000 | 01:00:00.0000 |
| jon | ListUpdater | 2016-02-25 15:36:00.0000 | 2016-02-25 16:06:00.0000 | 00:30:00.0000 |
| jon | Resolver | 2016-02-25 05:00:00.0000 | 2016-02-26 05:00:00.0000 | 24:00:00.0000 |
| dan | Resubmitter | 2016-02-25 15:55:30.0000 | 2016-02-25 16:55:30.0000 | 01:00:00.0000 |
| admin | NetworkExecutor | 2016-02-25 06:10:00.0000 | 2016-02-26 06:10:00.0000 | 24:00:00.0000 | | admin | AUpdater | 2016-02-21 03:00:00.0000 | 2016-02-28 03:00:00.0000 | 168:00:00.0000 |
| admin | alexaweb | 2016-02-25 15:55:36.0000 | 2016-02-25 15:56:36.0000 | 00:01:00.0000 |