运行时,它与条件不匹配。
它跳过它并运行“else”块。如果条件未评估
你能帮我吗?
public class LoginActivity extends AppCompatActivity {
private EditText usern;
private EditText passw;
private Button logButton;
@Override
protected void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
usern = (EditText) findViewById(R.id.userNameText);
passw = (EditText) findViewById(R.id.passwordText);
logButton = (Button) findViewById(R.id.loginButton);
logButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
if(usern.getText().toString().equals("demo") && passw.getText().equals("demo")){
Intent intent = new Intent(LoginActivity.this, MainActivity.class);
startActivity(intent);
Toast.makeText(getApplicationContext(), "Login...", Toast.LENGTH_SHORT).show();
}
else{
Toast.makeText(getApplicationContext(), "Username or password incorrect", Toast.LENGTH_SHORT).show();
}
}
});
}
}
详细描述你的问题....什么是预期的行为什么是实际行为等... – Plirkee