不行我有一个查询,在phpmyadmin的工作,但不能在PHP的工作(mysqli
)MySQL查询工作,但在库MySQLi
问题出在哪里?
查询:
INSERT INTO `SepidarSoft_Portal`.`Archive_Media` SET `CTime`='1364135670',`UTime`='1364135670',`PID`='',`State`='1',`Sequence`='0',`Subject`='Hojom Marg (www.Parstafrih.ir)',`Text`='',`Description`='',`Definition`='',`KeyWord`='',`ETag`='',`Access`='',`LinkToPage`='',`Attachment`='[{\"Name\":null,\"Kind\":null,\"Size\":false,\"Address\":\"27\",\"More\":{\"Original\":1}}]',`STime`='0',`ETime`='0';
SET @LAST_ID:=LAST_INSERT_ID();
INSERT INTO `SepidarSoft_Portal`.`Archive_Media_MoreInfo` (`id`,`Key`,`Value`) VALUES (@LAST_ID,'Instrumental','1'),(@LAST_ID,'KindFile','صوتی'),(@LAST_ID,'Genre','نغمه'),(@LAST_ID,'SName','Amir Tajik (www.Parstafrih.ir)'),(@LAST_ID,'Events','[[\"\"]]'),(@LAST_ID,'Album','(www.Parstafrih.ir)'),(@LAST_ID,'Composer',''),(@LAST_ID,'Adjustment',''),(@LAST_ID,'Subtitle','[object HTMLInputElement]'),(@LAST_ID,'Release','');
错误:
#1064 -You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SET @LAST_ID:=LAST_INSERT_ID();
1)我使用PHP mysqli_multi_query
这个
你插入MySQL的一个可能的'''? – samayo 2013-03-24 14:46:14
@phpNoOb不,这是通过'\'插入查询的输出' – 2013-03-24 14:49:38
我不明白为什么有人低估了这个问题! – 2013-03-24 14:54:50