我正在做我的项目来实现一个打字导师应用在Turbo C编译器 (这是限制),这个函数实际上是一个查找表的x,y和关键字符,但它返回我在参数中传递的第一个值的垃圾值。 从第二开始就开始做对了。 请注意,x,y是在时间返回两个值的指针。 请检查我的错误是什么。问题发生在案例结构
s1 = "ASDF JKL; ADSF JLK; ";
char take_xy(char s1[], int j, int *x, int *y)
{
char ch;
switch(s1[j])
{
case 'Q' : *x = 137; *y = 244; ch = 'Q'; break;
case 'W' : *x = 160; *y = 244; ch = 'W'; break;
case 'E' : *x = 183; *y = 244; ch = 'E'; break;
case 'R' : *x = 206; *y = 244; ch = 'R'; break;
case 'T' : *x = 229; *y = 244; ch = 'T'; break;
case 'Y' : *x = 252; *y = 244; ch = 'Y'; break;
case 'U' : *x = 275; *y = 244; ch = 'U'; break;
case 'I' : *x = 298; *y = 244; ch = 'I'; break;
case 'O' : *x = 321; *y = 244; ch = 'O'; break;
case 'P' : *x = 344; *y = 244; ch = 'P'; break;
case 'A' : *x = 144; *y = 268; ch = 'A'; break;
case 'S' : *x = 167; *y = 268; ch = 'S'; break;
case 'D' : *x = 190; *y = 268; ch = 'D'; break;
case 'F' : *x = 213; *y = 268; ch = 'F'; break;
case 'G' : *x = 236; *y = 268; ch = 'G'; break;
case 'H' : *x = 259; *y = 268; ch = 'H'; break;
case 'J' : *x = 282; *y = 268; ch = 'J'; break;
case 'K' : *x = 305; *y = 268; ch = 'K'; break;
case 'L' : *x = 328; *y = 268; ch = 'L'; break;
case ';' : *x = 351; *y = 268; ch = ';'; break;
// case ''' : *x = 374; *y = 268; ch = '''; break;
case 'Z' : *x = 162; *y = 292; ch = 'Z'; break;
case 'X' : *x = 185; *y = 292; ch = 'X'; break;
case 'C' : *x = 208; *y = 292; ch = 'C'; break;
case 'V' : *x = 231; *y = 292; ch = 'V'; break;
case 'B' : *x = 254; *y = 292; ch = 'B'; break;
case 'N' : *x = 277; *y = 292; ch = 'N'; break;
case 'M' : *x = 300; *y = 292; ch = 'M'; break;
case '?' : *x = 369; *y = 292; ch = '?'; break;
case ' ' : *x = 189; *y = 316; ch = ' '; break;
}
return ch;
}
发布您用来调用它的代码。我也不明白你为什么在函数外有一个单独的's1'变量。 – 2010-09-12 02:18:50
顺便说一下,它看起来像你可以删除所有'ch ='...''语句,并且只是从这个函数返回s1 [j]';但正如马修所说,它看起来很好,所以问题可能出在调用'take_xy'的代码中,而不是函数本身。 – 2010-09-12 02:27:16