WHERE语句在左外连接中的位置

在下面的查询中，我试图首先筛选network_id = 24的所有订阅，然后将payment_plans.plan_type列加入到订阅中ids相同的订阅中。WHERE语句在左外连接中的位置

我认为这是在WHERE声明的定位问题，但我不知道它在哪里 - 错误表明存在连接语句附近的语法错误

任何建议，其中错误可能是？

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type 
FROM subscriptions WHERE network_id = 24 
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id 


ERROR: syntax error at or near "LEFT" 
LINE 3: LEFT OUTER JOIN payment_plans ON subscription.payment_plan_i... 
     ^

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2017-04-03 the_darkside

在哪个表中是'network_id'列？ –

您的查询应该是：

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type 
FROM subscriptions 
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id 
WHERE network_id = 24

您可以检查出documentation for the SELECT statement, in particular this section。

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2017-04-03 08:27:39 mrina713

SQL的语法是select ... from ... join .. on ..where。

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type 
FROM subscriptions 
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id 
WHERE network_id = 24

即所有RDBMS的SQL标准和相同。

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2017-04-03 08:23:45 Jens

@Downvoter：请解释原因！ – Jens

我们都发布了相同的答案。你为什么会陷入低迷，它超越了我。 – Palethorn

在连接语句后移动您的位置。就像这样：

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, 
payment_plans.plan_type 
FROM subscriptions 
LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = 
payment_plans.id 
WHERE network_id = 24

来源

2017-04-03 08:24:17 Palethorn

你可以试试这个

SELECT DISTINCT subscriptions.user_id, subscriptions.payment_plan_id, payment_plans.plan_type FROM subscriptions LEFT OUTER JOIN payment_plans ON subscription.payment_plan_id = payment_plans.id WHERE subscriptions.network_id = 24

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2017-04-03 08:25:13 user3441151

WHERE语句在左外连接中的位置

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