如何将系列列表转换为列表？

Question

我有一系列的列表：

[0 1.738976 
1 1.230319 
2 1.238717 
3 1.224020 
4 1.071875 
dtype: float64, 5 1.132621 
6 1.116945 
7 0.922949 
8 1.101268 
9 1.065996 
dtype: float64, 10 1.020927 
11 1.022459 
12 1.034100 
13 0.995297 
14 1.036040 
dtype: float64, 15 1.245819 
16 1.364338 
17 0.989574 
18 1.024846 
19 0.979776 
dtype: float64, 20 1.583318 
21 1.561273 
22 1.795929 
23 1.769475 
24 1.757718 
dtype: float64, 25 1.040522 
26 1.022886 
27 0.724544 
28 0.718666 
29 0.736302 
dtype: float64, 30 0.721605 
31 0.842607 
32 0.827911 
33 0.818113 
34 2.153058 
dtype: float64, 35 2.303698 
36 2.402411 
37 2.233889 
38 3.288128 
39 2.579750 
dtype: float64] 

我想把系列的所有值在一个列表。我试过了：

a = [list_of_series] 
a1 = reduce(lambda x, y: x+y, a) 

但是输出的是nan值。

Answer 1

我想你需要concat：

s = pd.concat(L) 

---

L = [s1,s2,s3] 
print (L) 
[0 1.738976 
1 1.230319 
2 1.238717 
3 1.224020 
4 1.071875 
Name: val, dtype: float64, 5 1.132621 
6 1.116945 
7 0.922949 
8 1.101268 
9 1.065996 
Name: val, dtype: float64, 10 1.020927 
11 1.022459 
12 1.034100 
13 0.995297 
14 1.036040 
Name: val, dtype: float64] 

s = pd.concat(L) 
print (s) 
0  1.738976 
1  1.230319 
2  1.238717 
3  1.224020 
4  1.071875 
5  1.132621 
6  1.116945 
7  0.922949 
8  1.101268 
9  1.065996 
10 1.020927 
11 1.022459 
12 1.034100 
13 0.995297 
14 1.036040 
Name: val, dtype: float64 

print ([s]) 
[0  1.738976 
1  1.230319 
2  1.238717 
3  1.224020 
4  1.071875 
5  1.132621 
6  1.116945 
7  0.922949 
8  1.101268 
9  1.065996 
10 1.020927 
11 1.022459 
12 1.034100 
13 0.995297 
14 1.036040 
Name: val, dtype: float64]