$sth = $db->prepare("SELECT tblCompanies.*, users.Username, cargo.Name, (tblCompanies.Money + SUM(tblCTerminals.sellValue)) as assets, (COUNT(tblFinishedContracts.ID) + COUNT(tblFinishedSubContracts.ID)) as completed FROM ((((tblCompanies LEFT JOIN users ON tblCompanies.CompanyCEO = users.ID) LEFT JOIN cargo ON (tblCompanies.PreferredCargo = cargo.Cargo_ID)) LEFT JOIN tblCTerminals ON (tblCompanies.Company_ID = tblCTerminals.companyID)) LEFT JOIN tblFinishedContracts ON (tblCompanies.Company_ID = tblFinishedContracts.companyID)) LEFT JOIN tblFinishedSubContracts ON (tblCompanies.Company_ID = tblFinishedSubContracts.companyID) WHERE (users.Username LIKE :info || tblCompanies.CompanyName LIKE :info2 || CONCAT('$',FORMAT((tblCompanies.Money + SUM(tblCTerminals.sellValue)),2)) LIKE :info3 || CONCAT('$',FORMAT(tblCompanies.Money,2)) LIKE :info4 || cargo.Name LIKE :info5 || users.pLevel LIKE :info6 || CONCAT('$',FORMAT((users.Cash_In_Bank + users.Cash_In_Hand),2)) LIKE :info7)");
$sth->bindValue(':info', '%'.$_GET['sSearch'].'%', PDO::PARAM_STR);
$sth->bindValue(':info2', '%'.$_GET['sSearch'].'%', PDO::PARAM_STR);
$sth->bindValue(':info3', '%'.$_GET['sSearch'].'%', PDO::PARAM_STR);
$sth->bindValue(':info4', '%'.$_GET['sSearch'].'%', PDO::PARAM_STR);
$sth->bindValue(':info5', '%'.$_GET['sSearch'].'%', PDO::PARAM_STR);
$sth->bindValue(':info6', '%'.$_GET['sSearch'].'%', PDO::PARAM_STR);
$sth->bindValue(':info7', '%'.$_GET['sSearch'].'%', PDO::PARAM_STR);
好了,所以现在我的推理这个烂摊子:多个左连接的问题
我使用jQuery Datatables插件,当它的请求到服务器发送查询。它期望返回结果,搜索查询中有多少个结果以及多少个结果。有了这个查询,我可以返回结果。
但是在COUNT(tblFinishedContracts.ID)上,它抓取表8次。因此,例如,而不是返回的8正确的金额它返回的112
计数当我这样做:
SELECT COUNT(tblFinishedContracts.ID)
FROM tblCompanies
LEFT JOIN tblFinishedContract
ON (tblCompanies.Company_ID = tblFinishedContracts.ID)
WHERE tblCompanies.Company_ID = 11
它的工作原理,它返回8.如果有人知道这样做的更好的方法是什么我试图完成或可以告诉我如何解决这个问题,这将不胜感激!
感谢,
杰夫
编辑:添加,没有列重名的一切都不同了。
好吧,这就是我现在的,我得到一个错误,说附近检查正确的语法“SELECT 1 FROM tblFinishedSubContracts WHERE companyID = tblCompanies.Company_ID)'”:'SELECT COUNT(SELECT 1 FROM tblFinishedSubContracts WHERE (tblCompanies LEFT JOIN cargo ON(tblCompanies.PreferredCargo = cargo.Cargo_ID))LEFT JOIN tblCTerminals ON(tblCompanies.Company_ID = tblCTerminals.companyID))LEFT JOIN用户ON tblCompanies.CompanyCEO = users.ID )WHERE tblCompanies.Company_ID = 7'不太确定它有什么问题。 – jefffan24 2012-03-17 20:05:41
@ jefffan24:我的错:我遗漏了一对括号。 'COUNT(SELECT ...)'应该是COUNT((SELECT ...))'(一对属于'COUNT',分隔它的参数;另一个属于子查询,标记为这样)。我纠正了我的答案。 – ruakh 2012-03-17 20:14:47
新问题:子查询返回多于1行...可以计算处理该类型的子查询吗? – jefffan24 2012-03-17 20:18:04