2014-11-03 97 views
0

我有两个表区域(名称,编号),城市(地区编号,姓名,人口),我想返回人口最多的前5个城市以及该地区的名称。这是我的查询,但它只返回一个区域的5个城市(北在这种情况下),而不是所有地区:限制一列的结果

SELECT region.name AS region_name, city.name AS city_name, city.population AS population 
FROM region INNER JOIN (SELECT city.name, city.population, city.region_code 
FROM county LIMIT 5) AS city 
ON region.code = city.region_code; 

所需的输出:

 region_name |  city_name   | population 
------------+----------------------------+------------ 
NORTH  | A       |  226338 
NORTH  | B       |  13656 
NORTH  | C       |  9478 
NORTH  | D       |  2464 
NORTH  | E       |  2464 
WEST  | A       |  226338 
WEST  | B       |  13656 
WEST  | C       |  9478 
WEST  | D       |  2464 
WEST  | E       |  2464 

感谢您对您的帮助提前:)

回答

2

作为一般规则,不要使用limit而不使用order by。你得到五个任意城市。

你想要做的是在MySQL中有点痛苦。以下应工作,虽然:

SELECT r.name AS region_name, c.name AS city_name, c.population AS population 
FROM region r INNER JOIN 
    county c 
    ON r.code = c.region_code 
WHERE 5 >= (SELECT count(*) 
      FROM county c2 
      WHERE c2.region_code = c.region_code and c2.population >= c.population 
      ) 
ORDER BY region, population DESC; 

where条款与计数大于给定城市一样大或更大的人口的城市的数量。返回的唯一城市是前5名。

+0

它的工作,非常感谢你:) – Mera 2014-11-04 06:01:19

2

LIMIT是你的SQL关键字朋友,使用SELECT ... ORDER BY population LIMIT 5