我已经看过一些其他类似的问题,但仍似乎无法得到它的工作。 FWIW,我没有收到任何具体的错误信息。PHP的MySQLi没有插入表
<?php
// Create connection
$con=mysqli_connect("localhost","username","password");
mysqli_select_db($con, "database");
//let's start our session, so we have access to stored data
session_start();
$class = mysqli_real_escape_string($_SESSION['exclass']);
$fullname = mysqli_real_escape_string($_SESSION['fullname']);
$june = mysqli_real_escape_string($_SESSION['June']);
$july = mysqli_real_escape_string($_SESSION['July']);
$email = mysqli_real_escape_string($_POST['email']);
$phone = mysqli_real_escape_string($_POST['phone']);
//let's create the query
$insert_query = "INSERT INTO Responses (class,fullname,June,July,email,phone) VALUES ('$class','$fullname',$june,$july,'$email','$phone',)";
//let's run the query
$result = mysqli_query($con,$insert_query);
if($result){
echo "Your response has been recorded. Thank you!";
}else{
printf("Insert failed: %s\n", mysqli_error());
}
?>
当你通过命令行或者像phpmyadmin这样的工具直接在MySQL中运行查询时会发生什么? – 2013-03-07 17:27:40
''$ phone''后面有一个尾随逗号,它打破了查询。不知道为什么你没有看到错误信息,但应该报告一个语法错误。 – 2013-03-07 17:28:53
你有没有把'$ june,$ july'放在单引号中的原因? – PGallagher 2013-03-07 17:28:56