下面的程序理论上应该创建一个链接列表,然后用户可以添加,显示或减去(不相关)。目前我的问题是试图让我的链表上打印多个值。链接列表更改节点而不是添加另一个
主要问题我很肯定来自函数add_node,但我似乎无法让它根本改变。 (有一个减法类选项,但我省略了该函数,因为它没有关系。)
我需要更改哪些内容才能添加到链接列表中?
任何帮助,将不胜感激
#include <iostream>
#include <cstring>
struct ToDoList
{
std::string start_time;
std::string activity_name;
int time_for_activity;
ToDoList *next;
};
void add_node(ToDoList * & head, std::string start, std::string activity,int time)
{
ToDoList* temp;
head = new ToDoList;
temp = new ToDoList;
head-> start_time = start;
head-> activity_name = activity;
head-> time_for_activity = time;
head-> next = head;
head = temp;
temp = temp->next;
head->next=NULL;
}//in theory this should add another node to the list but it isn't working
int main()
{
int ans, i = 0;
std::string start;
std::string activity;
int time;
ToDoList* head;
ToDoList* a;
std::cout << "Enter the start time in HH:MM am format: ";
std::getline(std::cin, start);
std::cout << "Enter the activity name: ";
std::getline(std::cin, activity);
std::cout << "Enter the time for the activity: ";
std::cin >> time;
//~ add_node(head);
add_node(head,start,activity,time);
std::cout << "\nWelcome to the Linked list menu! What would you like to do? \n0 Add a Node \n1 Display the list \n2 Delete a node \n3 Quit \n";
std::cin >> ans;
while(ans != 3)//This should print all the values in the list
{
std::cin.ignore();
if(ans == 0)
{
std::cout << "Enter the start time in HH:MM am format: ";
std::getline(std::cin, start);
std::cout << "Enter the activity name: ";
std::getline(std::cin, activity);
std::cout << "Enter the time for the activity: ";
std::cin >> time;
add_node(head,start,activity,time);
}
else if(ans == 1)
{
a = new ToDoList;//creates new pointer for while loop
a = head;
while(a != NULL)//loop used for printing
{
std::cout << i << " " << a->start_time << " " << a->activity_name << " " << a->time_for_activity << "\n";
a = a -> next;
i++;
}
i = 0;//resets integer i
}
std::cout << "\nWelcome to the Linked list menu! What would you like to do? \n0 Add a Node \n1 Display the list \n2 Delete a node \n3 Quit \n";
std::cin >> ans;
}
return 0;
}
到目前为止,它只能打印以下内容:
head = new ToDoList;
您可以:
Enter the start time in HH:MM am format: 10:00 am
Enter the activity name: Office Hours
Enter the time for the activity: 30
Welcome to the Linked list menu! What would you like to do?
0 Add a Node
1 Display the list
2 Delete a node
3 Quit
0
Enter the start time in HH:MM am format: 11:00 am
Enter the activity name: Lunch
Enter the time for the activity: 60
Welcome to the Linked list menu! What would you like to do?
0 Add a Node
1 Display the list
2 Delete a node
3 Quit
1
0 0
test
教程[here](http://pastebin.com/DXunz58Q) – sp2danny