我有一个查询MySQL数据库的PHP搜索脚本。目前,当没有显示结果时,脚本显示并显示错误。如何在没有返回任何内容时显示“找不到结果”的消息?在PHP中找不到结果时显示信息MySQL搜索
我的PHP脚本是:
<?php
mysql_connect("localhost","username","password");
mysql_select_db("database");
if(!empty($_GET['q'])){
$query=mysql_real_escape_string(trim($_GET['q']));
$searchSQL="SELECT * FROM links WHERE `title` LIKE '%{$query}%' LIMIT 8";
$searchResult=mysql_query($searchSQL);
while ($row=mysql_fetch_assoc($searchResult)){
$results[]="<div class='webresult'><div class='title'><a href='{$row['url']}'>{$row['title']}</a></div><div class='desc'>{$row['description']}</div><div class='url'>{$row['url']}</div></div>";
}
echo implode($results);
}
?>
mysql_num_result – dynamic