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我有一个数据结构中的可变$xml
,看起来像这样:如何在PHP中引用XML对象内的XML对象?
object(SimpleXMLElement)#3 (1) {
["release"]=>
object(SimpleXMLElement)#4 (11) {
["@attributes"]=>
array(1) {
["id"]=>
string(36) "49d996b2-ab53-41bd-8789-3d87938dc07d"
}
["title"]=>
string(9) "Pinkerton"
["status"]=>
string(8) "Official"
["packaging"]=>
string(10) "Jewel Case"
["quality"]=>
string(6) "normal"
["text-representation"]=>
object(SimpleXMLElement)#5 (2) {
["language"]=>
string(3) "eng"
["script"]=>
string(4) "Latn"
}
["artist-credit"]=>
object(SimpleXMLElement)#6 (1) {
["name-credit"]=>
object(SimpleXMLElement)#7 (1) {
["artist"]=>
object(SimpleXMLElement)#8 (3) {
["@attributes"]=>
array(1) {
["id"]=>
string(36) "6fe07aa5-fec0-4eca-a456-f29bff451b04"
}
["name"]=>
string(6) "Weezer"
["sort-name"]=>
string(6) "Weezer"
}
}
}
["date"]=>
string(10) "1996-09-24"
["country"]=>
string(2) "US"
["barcode"]=>
string(12) "720642500729"
["asin"]=>
string(10) "B000000OVP"
}
}
我将如何引用名“Weezer乐队”在这里吗?或排序名称?
这里是我的尝试:用连字符
$a = (array)$xml->release['artist-credit']; // nothing
$a = $xml->release['artist-credit']; // nothing
$a = (array)$xml->release->artist-credit; // nothing
var_dump($a);
太好了,谢谢。 '$ a = $ xml-> release {'artist-credit'}'应该是'$ a = $ xml-> release - > {'artist-credit'}' – standardnerds 2012-03-20 21:15:38
另外,你知道它在引用中的位置'带连字符的属性需要用大括号'引用? – standardnerds 2012-03-20 21:16:11