我开发了一个servlet,其中的逻辑是:如果name等于saral saxena,那么它移动到下一页,否则不会,我在我的代码下面也发布,我想要一个变化就是它也应该是访问者号码,如果来自不同浏览器的两个不同用户访问同一网址,那么第二个访问者应该显示你是第二访问者。下面是我当前的代码..在servlet中添加用户计数器的功能
package trial;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class SendRedirectServlet
*/
public class SendRedirectServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
protected void doPost(HttpServletRequest request, HttpServletResponse
response)throws ServletException, IOException {
//System.out.println("*************");
response.setContentType("text/html");
PrintWriter pw = response.getWriter();
String name = request.getParameter("username");
pw.println("<br> this output is generated by a simple servlet.");
String password = request.getParameter("password");
if(name.equals("saral")&& password.equals("saxena")){
response.sendRedirect("/ValidUserServlet");
}
else{
pw.println("u r not a valid user");
}
}
}
其他的servlet是...
ackage trial;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class ValidUserServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter pw = response.getWriter();
pw.println("Welcome to roseindia.net " + " ");
pw.println("how are you");
}
}
和我的web.xml仪式现在是...
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<servlet>
<servlet-name>s1</servlet-name>
<servlet-class>trial.SendRedirectServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>s1</servlet-name>
<url-pattern>/SendRedirectServlet</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>s2</servlet-name>
<servlet-class>trial.ValidUserServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>s2</servlet-name>
<url-pattern>/ValidUserServlet</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>home.html</welcome-file>
</welcome-file-list>
</web-app>
最后我的html页面是...
<html>
<head>
<title>New Page 1</title>
</head>
<body>
<form method="post" action="/SendRedirectServlet">
<p>Enter your name
<input type="text" name="username" size="20"/></p>
<p>Enter your password <input type="text" name="password"
size="20"/></p>
<p>
<input type="submit" value="Submit" name="B1"/></p>
</form>
</body>
</html>
快照项目结构是..
http://imageshack.us/photo/my-images/707/49690689.jpg/
请告知如何你是访客人数
人请指教添加该功能。
欢迎roseindia.net?来吧,不要只是复制你在谷歌找到的代码... – MaVRoSCy 2012-07-23 05:34:47