2010-10-24 60 views
0

下面是我的C#作业本周的第5号草案。我首先使用Linq编写了程序,并且它运行良好。不幸的是,方向声明我必须创建自己的方法,而不是使用已经在Linq中找到的美妙Sum()方法。这个源代码的主要问题是方法重载不正确(也可能是我的整个Sum()方法也是错误的)。由于我们全能的文本没有清楚地解释如何重载这样的方法,我有点失落......(或者很多失败)。错误CS1501:我没有正确地重载Sum()方法

这里是赋值指令(再一次):

“创建接受任意数量的整数参数,并显示它们的总和)命名的总和(方法写演示和的Main()方法()方法当传递一个,三个,五个或十个整数的数组时,它会正常工作。将该程序保存为UsingSum.cs。“

从微软的Visual C#®2008年,介绍了面向对象程序设计,3E,乔伊斯·法雷尔

这里是我的源代码:

using System; 

public class UsingSum 
{ 
    public static void Main() 
    { 

     //Step 1: Adding 1, 3 and 5 

     int[] array1 = { 1, 3, 5 }; 

     int a; 
     int b; 
     int c; 
     int d; 
     int e; 
     int f; 
     int g; 
     int h; 
     int i; 
     int j;   
     int firstSum; 
     int secondSum; 

     Console.Write("When the numbers 1, 3 and 5 are added together, using the Sum() method, the answer is: "); 

     firstSum = Sum(array1); 
     Console.WriteLine("{0}", firstSum); 



     //Step 2: Entering variables into Array2[10] 


     Console.Write("Enter first integer for addition: "); 
     a = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter second integer for addition: "); 
     b = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter third integer for addition: "); 
     c = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter forth integer for addition: "); 
     d = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter fifth integer for addition: "); 
     e = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter sixth integer for addition: "); 
     f = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter seventh integer for addition: "); 
     g = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter eighth integer for addition: "); 
     h = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter ninth integer for addition: "); 
     i = Convert.ToInt32(Console.ReadLine()); 
     Console.Write("Enter tenth integer for addition: "); 
     j = Convert.ToInt32(Console.ReadLine()); 

     int[] array2 = { a, b, c, d, e, f, g, h, i, j }; 

     Console.Write("The total of {0} + {1} + {2} + {3} + {4} + {5} + {6} + {7} + {8} + {9} is: ", 
     a, b, c, d, e, f, g, h, i, j); 

     secondSum = Sum(array2); 
     Console.WriteLine("{0}", secondSum); 


    } 


//Step 3: Defining the Sum() method 

    public static int Sum(int a, int b) 

//My overload is generating error CS1501: No overload for method 'Sum' takes '1' arguments 

    { 

    int sum = 0; 
    int[] adder = new int[0]; 
//designating an array with no parameters... 

    for(int a = 0; a < adder.Length; ++a) 
     adder[a] = a; 

    foreach(int b in adder) 
     sum += b; 
     Console.WriteLine(" " + sum); 
    } 
} 

回答

1

您正在定义总和取2个参数

public static int Sum(int a, int b) 

但只有1个参数

firstSum = Sum(array1); 
012叫它

尝试定义琛采取的int数组:

public static int Sum(int[] input) 
+0

好吧,我给一个尝试:-)谢谢你这么清楚解释问题。 – Nooob 2010-10-24 17:33:54

+0

它的工作! :-)我忘了在最后加上回报。实际的Sum函数对任何事物都产生0,但我会想出来......谢谢你的帮助。 – Nooob 2010-10-24 17:37:57

+0

...我的源代码编译和工作完美。它生成0是因为我在foreach中引用了加法器数组(而在加法器中是int b)而不是引用用于重载Sum()方法的“输入”数组。非常感谢所有帮助我在本周末推出这些东西的人们。 :-) – Nooob 2010-10-24 18:04:12