如何在当前已订购的重复记录上添加行号列

Question

我想在一个记录中插入一个page_number，该记录可以基于列中的重复进行连续计数。示例输出：

ID  PAGE_ORDER PAGE_NUMBER 
1   7   1 
2   7   1 
3   7   1 
4   7   1 
5   7   1 
6   10   2 
7   10   2 
8   10   2 
9   10   2 
10   10   2 
11   13   3 
12   13   3 
13   13   3 
14   13   3 
15   13   3 
16   9   4 
17   9   4 
18   9   4 
19   9   4 
20   9   4 
21   16   5 
22   16   5 
23   16   5 
24   16   5 
25   16   5 
26   11   6 
27   11   6 
28   11   6 
29   11   6 
30   11   6 
31   12   7 
32   12   7 
33   12   7 
34   12   7 
35   12   7 
36   4   8 
37   4   8 
38   4   8 
39   4   8 
40   4   8 
41   5   9 
42   5   9 
43   5   9 
44   5   9 
45   5   9 
46   14   10 
47   14   10 
48   14   10 
49   14   10 
50   14   10 
51   15   11 
52   15   11 
53   15   11 
54   15   11 
55   15   11 
56   6   12 
57   6   12 
58   6   12 
59   6   12 
60   6   12 
61   1   13 
62   1   13 
63   1   13 
64   1   13 
65   1   13 
66   2   14 
67   2   14 
68   2   14 
69   2   14 
70   2   14 
71   8   15 
72   8   15 
73   8   15 
74   8   15 
75   8   15 
76   3   16 
77   3   16 
78   3   16 
79   3   16 
80   3   16 

如何在输出中添加page_number列？ page_number列的规则是基于page_order列中的重复记录连续计数。 请指教。谢谢。

Answer 1

我发现我的问题的解决方案：

select *, dense_rank() over (order by sort) 
from (select *, sort = min(ID) over (partition by page_order) 
     from #tbl) c 
order by c.ID 

由于KH谭在MSDN论坛。 http://social.msdn.microsoft.com/Forums/en-US/transactsql/thread/55a18861-50a1-4f8a-b6f7-16992fa51e94

谢谢你们伙计们！

Answer 2

我不太确定您的数据是如何订购的 - 似乎有很多重复，没有特定的顺序。

但是，如果你的SQL Server 2005或2008年，您的解决方案可能会涉及RANK

http://msdn.microsoft.com/en-us/library/ms176102.aspx

Answer 3

我在做什么用的ID柱确实有点不清楚，因为它总是相同的值，但是这应该给你你想要给你提供的数据输出：

WITH Results AS (
    SELECT 
     MAX(ID) as ID, 
     Page_Order, 
     ROW_NUMBER() OVER (ORDER BY Page_Order DESC) as Page_Number 
    FROM 
     PageNumberTable 
    GROUP BY 
     Page_Order 

) 
SELECT 
    Results.* 
FROM 
    PageNumberTable 
    JOIN Results ON PageNumberTable.Page_Order = Results.Page_Order 

Answer 4

试试这个

SELECT id, page_order, 
     DENSE_RANK() OVER(ORDER BY 
      (MIN(id) OVER(PARTITION BY page_order)) as page_number 
FROM table_name 
ORDER BY id 

编辑：试试这个，而不是

;WITH T1 AS 
(
    SELECT id, page_order, MIN(id) OVER(PARTITION BY page_order) AS min_id 
) 
SELECT id, page_order, DENSE_RANK() OVER(ORDER BY min_id) AS page_number 
FROM T1 
ORDER BY id