2017-08-22 70 views
0

我想创建一个mySQL查询来选择所有用户的信息(姓名,年龄,手机等),不包括“email”或“mobilePhone”上的重复项。在mySQL中隐藏重复条目

所以,我想避免显示重复条目的用户谁已经注册多次。

我的查询:

$sql = "SELECT tet.id tet_id, tet.firstName tet_fristName, tet.lastName tet_lastName,tet.image tet_image, 
         tet.url tet_url,tet.address tet_address,tet.job tet_job,tet.age tet_age, 
         tet.mobilePhone tet_mobilePhone, tet.homePhone tet_homePhone, tet.email tet_email, 
         tet.date_of_registration tet_date_of_registration, tet.player_id tet_player_id, 
         app.value app_value, app.date app_date 
       FROM `test_players` as tet 
       LEFT JOIN approved_test_players as app on app.player_id=tet.id WHERE app.value IS NULL order by tet.id desc "; 
$result = $conn->query($sql); 
+4

添加'在查询的开始选择DISTINCT'。 – KubiRoazhon

+0

您需要阅读'DISTINCT'和'GROUP BY'上的SQL手册。我相信这是你需要的后者。 –

回答

-1
Select id 
From table group by tel 
Having count(user_id)>2 
+0

你应该添加一些文字来解释你为什么认为你的代码能够回答这个问题(顺便说一下,它没有) –

0
SELECT DISTINCT tet.firstName as tet_fristName, tet.lastName as tet_lastName,tet.age as tet_age, tet.mobilePhone as tet_mobilePhone, tet.email as tet_email 

FROM `test_players` as tet 

JOIN approved_test_players as app 

ON app.player_id=tet.id 

WHERE app.value IS NULL 

order by tet.id desc 

试试这个