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我有一个iPhone应用程序,我试图去谈谈一个轨道后端。我使用NSMutableURLRequest来回拉取数据。所有的调用都可以很好地处理GET请求,但是当我需要发布数据时,我的rails应用程序似乎无法找到会话。我已经为get和POST请求发布了下面的代码。NSMutableURLRequest丢失会话信息
这是POST请求:
//Set up the URL
NSString *url_string = [NSString stringWithFormat:@"https://testserver.example.com/players.xml"];
NSURL *url = [NSURL URLWithString:url_string];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
cachePolicy:NSURLRequestReloadIgnoringCacheData
timeoutInterval:30];
//To create an object in rails
//We have to use a post request
////This is the format when using xml
NSString *requestString = [[NSString alloc] initWithFormat:@"<player><team_game_id>%@</team_game_id><person_id>%@</person_id></player>", game, person];
NSData *requestData = [NSData dataWithBytes:[requestString UTF8String] length:[requestString length]];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:requestData];
NSString *postLength = [NSString stringWithFormat:@"%d", [requestData length]];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
//For some reason rails will not take application/xml
[request setValue:@"application/xml" forHTTPHeaderField:@"content-type"];
GET请求是:
NSString *url_string = [NSString stringWithFormat:@"https://testserver.example.com/people/find_by_passport?passport=%i", passport];
passportString = [[NSMutableString alloc] initWithFormat:@"%i", passport];
NSLog(@"The passport string is %@", passportString);
NSLog(url_string, nil);
NSURL *url = [NSURL URLWithString:url_string];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url
cachePolicy:NSURLRequestReloadIgnoringCacheData
timeoutInterval:30];
我在我束手无策这里试图找出什么是继续下去,因此任何帮助,将不胜感激。
所以我有点明白我想在这里做什么,但我觉得我错过了一些东西,我把Set-Cookie放到一个字符串中,存储在一个钥匙链项目中,在下一个请求中选择它并将其添加到http标头字段中。这就是我需要做的一切,通过“手工提取饼干”你做了什么? – drapergeek
非常。另请参阅编辑。 –
其实我找到了同样的东西,我尝试将cookie添加回头部,但它似乎没有帮助我。 – drapergeek