正在验证我有一个有效的XSD和XML字符串与不同的架构。 如果我使用xml字符串并通过xmldocument.validate
尝试使用xsd模式进行验证,则不验证。用于测试books-debug.xml
XML字符串不是XSD
dim tmpdoc as new xmldocument()
dim abc as string= file.readalltext("books-debug.xml")
tmpdoc.schemas.add(nothing,"New.xsd")
Dim eventHandler As New ValidationEventHandler(AddressOf ValidationEventHandler)
tmpDoc.Validate(eventHandler)
End Sub
Private Shared Sub ValidationEventHandler(ByVal sender As Object, ByVal e As ValidationEventArgs)
Select Case e.Severity
Case XmlSeverityType.[Error]
MessageBox.Show("Error: {0}" + e.Message)
Exit Select
Case XmlSeverityType.Warning
MessageBox.Show("Warning {0}" + e.Message)
Exit Select
End Select
End Sub
XML:
<?xml version="1.0" encoding="UTF-8" ?>
<bookstore xmlns="http://myspace">
<debugparameters>
<parameter>
<paramname>paramname1</paramname>
<description>description1</description>
<subsystems>
<subsystem-id>g</subsystem-id>
<subsystem-id>f</subsystem-id>
<subsystem-id>d</subsystem-id>
</subsystems>
</parameter>
<parameter>
<paramname>paramname2</paramname>
<description>description2</description>
<subsystems>
<subsystem-id>f</subsystem-id>
<subsystem-id>g</subsystem-id>
<subsystem-id>d</subsystem-id>
</subsystems>
</parameter>
<parameter>
<paramname>paramname3</paramname>
<description>description3</description>
<subsystems>
<subsystem-id>f</subsystem-id>
<subsystem-id>g</subsystem-id>
<subsystem-id>d</subsystem-id>
</subsystems>
</parameter>
</debugparameters>
</bookstore>
的xsd:
<?xml version="1.0" encoding="utf-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" targetNamespace="http://www.contoso.com/books" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="bookstore">
<xs:complexType>
<xs:sequence>
<xs:element maxOccurs="unbounded" name="book">
<xs:complexType>
<xs:sequence>
<xs:element name="title" type="xs:string" />
<xs:element name="writer">
<xs:complexType>
<xs:sequence>
<xs:element minOccurs="0" name="name" type="xs:string" />
<xs:element minOccurs="0" name="first-name" type="xs:string" />
<xs:element minOccurs="0" name="last-name" type="xs:string" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="price" type="xs:decimal" />
</xs:sequence>
<xs:attribute name="genre" type="xs:string" use="required" />
<xs:attribute name="publicationdate" type="xs:date" use="required" />
<xs:attribute name="ISBN" type="xs:string" use="required" />
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>
你的XML中只有一个共同的与你的XML元素。你确定这是正确的实例或模式?命名空间也完全不同。 – helderdarocha
查看下面的模式是否解决了您的问题。如果没有,请用它编辑您的问题(因为您发布的内容不兼容)。 – helderdarocha
谢谢你的回复...我的问题是为什么我没有得到任何错误,即使架构不同于xml – projectTesting