我有一些XML如下。如果我知道title属性是:c4d5c5我如何获取模式属性(四)?js找到另一个属性的xml属性
<swatch title="af588b" name="color" width="50" height="50" mode="one"></swatch>
<swatch title="b1977c" name="color" width="50" height="50" mode="two"></swatch>
<swatch title="bfca64" name="color" width="50" height="50" mode="three"></swatch>
<swatch title="c4d5c5" name="color" width="50" height="50" mode="four"></swatch>
<swatch title="c5dbd9" name="color" width="50" height="50" mode="five"></swatch>
<swatch title="c181a4" name="color" width="50" height="50" mode="six"></swatch>
<swatch title="ca936c" name="color" width="50" height="50" mode="seven"></swatch>
是这样的吗? (这不工作,但我就是这样的时刻,)
$(xmlDoc).find('swatch').each(function() {
var myMode = $(xmlDoc).find('mode[title="c4d5c5"]');
console.log(myMode+" myMode");
});
属性值是有一个嘟嘟元素为xml – 2014-09-01 02:52:27