2011-06-13 49 views

回答

0
select user_email,';' from user_list where other = 'Y' 
+0

谢谢。我对这一切都很陌生:-) – Terry 2011-06-13 10:08:22

1
DECLARE @List varchar(max) 

SET @List = '' 

SELECT @List = @List + ';' + user_email FROM user_list WHERE other = 'Y' 

SET @List = SUBSTRING(@List, 2, 2000000000) 

SELECT @List