vba访问显示与最短日期重复的数据

Question

有什么办法找到最小（创建日期）并从访问查询中删除它？

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Answer 1

您可以简单地使用MIN（）函数MIN（）日期选择记录。

SELECT Item_Number, Order_Number, Order_Line_Number, MIN(Creation_Date) 
FROM *tblName* 
GROUP BY Item_Number, Order_Number, Order_Line_Number 

或者您可以在'创建日期'列上使用MAX（）函数来排除具有最小日期的记录。

SELECT Item_Number, Order_Number, Order_Line_Number, MAX(Creation_Date) 
FROM *tblName* 
GROUP BY Item_Number, Order_Number, Order_Line_Number 

或者如果您最初提到的真的想从MIN（）日期删除MS Access表中的记录然后使用下面的查询。

DELETE **tbl_A.*** FROM 
*tblName tbl_A* INNER JOIN *tblName tbl_B* 
WHERE 
tbl_A.Item_Number = tbl_B.Item_Number 
AND 
tbl_A.Order_Number = tbl_B.Order_Number 
AND 
tbl_A.Order_Line_Number = tbl_B.Order_Line_Number 
AND 
tbl_A.Creation_Date = tbl_B.MIN(Creation_Date)