在perl中指数求一个矩阵

我正在寻找一个使用perl来求矩阵的函数。我搜查了CPAN，但似乎无法找到任何合适的东西。有谁知道一个合适的包装，或简单的功能？在perl中指数求一个矩阵

例如，对于下面的矩阵（$ M）：

$m = [[-1.85294,0.36417,1.34865,0.14012], 
     [0.13385,-0.70885,0.16502,0.40998], 
     [0.48588,0.16174,-0.77471,0.12709], 
     [0.13424,1.06859,0.33797,-1.54081]];

E 1米〜=

0.25438971 0.2029723 0.4580481 0.08458940 
0.07460393 0.6061030 0.1588883 0.16040370 
0.16502112 0.1557330 0.6025270 0.07671839 
0.08103971 0.4180838 0.2040153 0.29685570

来源

2012-02-23 wannymahoots

http://search.cpan.org/~ellipse/PDL-LinearAlgebra-0.06/Trans/trans.pd#mexp或http://www.davideous.com/matrixexp/matrix.pm？ – 2012-02-23 18:18:07

PDL将处理这一点，因为@ J.D。指出。

use strict; 
use warnings; 

use PDL; 
use PDL::LinearAlgebra::Trans; 
use PDL::IO::Dumper; 

my $m = pdl [[-1.85294,0.36417,1.34865,0.14012], 
      [0.13385,-0.70885,0.16502,0.40998], 
      [0.48588,0.16174,-0.77471,0.12709], 
      [0.13424,1.06859,0.33797,-1.54081]]; 

my $new = mexp $m; 

print sdump $new;

结果：

{my($VAR1); 
my($PDL_140600590505856) = (double(0.254389714179579,0.202972289234997,0.458048094091295,0.08458940315894629,0.0746039289026906,0.606102994157082,0.158888283526803,0.160403695685552,0.165021120118487,0.155733015860466,0.602527027489139,0.07671838765811791,0.08103970821403091,0.418083774202018,0.204015347133539,0.296855703714981)->reshape(4,4)); 


$VAR1 = $PDL_140600590505856; 

}

的double()函数内的比特是结果矩阵。

来源

2012-02-23 20:14:38 friedo

这样做。它似乎打印了三条关于被重定义的子路由器的警告。我相信它没有什么可担心的，但是你知道一种防止这种情况的方法吗？谢谢！ – wannymahoots 2012-02-23 20:59:02

奇怪。我没有得到任何警告，在5.14.2下运行它。你使用的是什么版本的Perl和PDL？ – friedo 2012-02-24 00:30:17

我正在运行perl v5.12.4，但可能会出现一些与我的安装PDL（主要安装在Ubuntu上使用apt-get，但从源安装PDL :: LinearAlgebra :: Trans）。我会调查...... – wannymahoots 2012-02-24 12:00:13

在perl中指数求一个矩阵

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