Python：发送图像文件的请求

我有一个服务器，我正在尝试建立一个发送请求以获取数据。我认为实现这一目标的一种方法是在头中添加参数并发出请求。但是我收到了很少的错误，我不能很好地理解这些错误。Python：发送图像文件的请求

HTML表单

<html> 
<head> 
<meta http-equiv="content-type" content="text/html; charset=ISO-8859-1"> 
    </head> 
    <body> 
    <form method="POST" action="http://some.server.com:61235/imgdigest" enctype="multipart/form-data"> 
     quality:<input type="text" name="quality" value="2"><br> 
     category:<input type="text" name="category" value="1"><br> 
     debug:<input type="text" name="debug" value="1"><br> 
     image:<input type="file" name="image"><br> 
     <input type="submit" value="Submit"> 
    </form> 
    </body> 
</html>

Python代码：我已编辑基于答案

import urllib, urllib2 
import base64 

if __name__ == '__main__': 
    page = 'http://some.site.com:61235/' 
    with open("~/image.jpg", "rb") as image_file: 
     encoded_image = base64.b64encode(image_file.read()) 
    raw_params = {'quality':'2','category':'1','debug':'0', 'image': encoded_image} 
    params = urllib.urlencode(raw_params) 
    request = urllib2.Request(page, params) 
    request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8") 
    page = urllib2.urlopen(request) 
    info = page.info()

错误的问题：

page = urllib2.urlopen(request) 
    File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen 
    return _opener.open(url, data, timeout) 
    File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 406, in open 
    response = meth(req, response) 
    File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 519, in http_response 
    'http', request, response, code, msg, hdrs) 
    File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 444, in error 
    return self._call_chain(*args) 
    File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 378, in _call_chain 
    result = func(*args) 
    File "/opt/local/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 527, in http_error_default 
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) 
urllib2.HTTPError: HTTP Error 404: Not Found

来源

2012-07-18 Null-Hypothesis

那么使用encoded_image而不是“~/image.jpg”，一方面，图像需要有一个图像，而不是一个字符串。我会建议尝试请求，而不是使用urllib，urllib2。 http://docs.python-requests.org/en/latest/index.html – sberry 2012-07-18 22:27:44

添加这个头：

request.add_header("Content-type", "application/x-www-form-urlencoded; charset=UTF-8")

此外，您发送的图像参数是一个字符串，而不是图像文件的内容。你需要B64编码它

import base64 

with open("image.jpg", "rb") as image_file: 
    encoded_image = base64.b64encode(image_file.read())

然后在raw_params

来源

2012-07-19 20:53:26

所以我应该在request = urllib2.Request（page，params）之后将它添加到头部？ – 2012-07-19 21:53:01

我做了更改，但仍然收到相同的错误。 – 2012-07-19 23:21:37

确保您在Python代码中使用的网址与html表单中的操作属性完全相同。看起来你正在Python中添加'.html'。 – 2012-07-20 15:08:52

Python：发送图像文件的请求

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