我怎么能计算出一个嵌套的SQL语句的平均？

Question

我有这个疯狂的嵌套的SQL语句，并返回是这样的：

不过，我要的是使用该数据的图像在返回2列。 COL_1：SUM(avgWithCriteria)/43和COL_2：SUM(avgWithoutCriteria)/43。我如何通过添加到我的查询下面？

SELECT 
    ((avgWithCriteria - totalAverage)/((avgWithCriteria + totalAverage)/2)) * 100 as percentDifference, 
    a.* 
FROM 
    (SELECT 
     AVG(CASE WHEN 'f' not in (has_free_parking) THEN price ELSE null END) as avgWithCriteria, 
     AVG(CASE WHEN 'f'  in (has_free_parking) THEN price ELSE null END) as avgWithoutCriteria, 
     AVG(price) as totalAverage, 
     neighbourhood_cleansed 
    FROM listings 
    WHERE city_name="berlin" 
    AND price <= 1000000 
    AND price >= -1 
    AND reviews_per_month <= 1000000 
    AND reviews_per_month >= -1 
    AND est_monthly_income <= 1000000 
    AND est_monthly_income >= -1 
    GROUP BY neighbourhood_cleansed) a; 

Answer 1

试试这个： - 。

SELECT percentDifference,avgWithCriteria,avgWithoutCriteria,totalAverage,neighbourhood_cleansed, 
(col1_1/43) as col1,(col2_2/43) as col2 
from 
(
SELECT a.*,SUM(avgWithCriteria) as col1_1,SUM(avgWithoutCriteria) as col2_2 
FROM 
    (
SELECT 
    ((avgWithCriteria - totalAverage)/((avgWithCriteria + totalAverage)/2)) * 100 as percentDifference, 
    a.* 
FROM 
    (SELECT 
     AVG(CASE WHEN 'f' not in (has_free_parking) THEN price ELSE null END) as avgWithCriteria, 
     AVG(CASE WHEN 'f'  in (has_free_parking) THEN price ELSE null END) as avgWithoutCriteria, 
     AVG(price) as totalAverage, 
     neighbourhood_cleansed 
    FROM listings 
    WHERE city_name="berlin" 
    AND price <= 1000000 
    AND price >= -1 
    AND reviews_per_month <= 1000000 
    AND reviews_per_month >= -1 
    AND est_monthly_income <= 1000000 
    AND est_monthly_income >= -1 
    GROUP BY neighbourhood_cleansed) a 
) a 
GROUP BY percentDifference,avgWithCriteria,avgWithoutCriteria,totalAverage,neighbourhood_cleansed 
) a; 

Answer 2

SELECT 
    ((avgWithCriteria - totalAverage)/((avgWithCriteria + totalAverage)/2)) * 100 as percentDifference, 
    SUM(avgWithCriteria)/43 AS col_1, 
    SUM(avgWithoutCriteria)/43 AS col_2, 
    a.* 
FROM 
    (SELECT 
     AVG(CASE WHEN 'f' not in (has_free_parking) THEN price ELSE null END) as avgWithCriteria, 
     AVG(CASE WHEN 'f'  in (has_free_parking) THEN price ELSE null END) as avgWithoutCriteria, 
     AVG(price) as totalAverage, 
     neighbourhood_cleansed 
    FROM listings 
WHERE city_name="berlin" 
AND price <= 1000000 
AND price >= -1 
AND reviews_per_month <= 1000000 
AND reviews_per_month >= -1 
AND est_monthly_income <= 1000000 
AND est_monthly_income >= -1 
GROUP BY neighbourhood_cleansed) a;