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这里的product_id是我的查询组通过,但保存的所有记录某处
select p.product_id, ts.name as my_name, ss.step_number, p.specs, SUM(p.price), ssp.class_id
from optional_system_step as ss
join system as s on s.system_id=ss.system_id
join category_description as cd on cd.category_id=ss.category_id
join optional_system_step_product as ssp on ss.system_step_id=ssp.system_step_id
join product as p on p.product_id=ssp.product_id
join product_description as pd on pd.product_id=p.product_id
join template_step as ts on (ts.template_id=s.optional_template_id and ts.step_number=ss.step_number)
where s.system_id = '15'
GROUP BY ssp.class_id, ss.step_number
order by ss.step_number, ssp.class_id;
返回正确的总和,但它只返回PRODUCT_ID的
78 sdzvzcxv 1 4047.0000 1
143 sdzvzcxv 1 628.0000 2
59 sdzvzcxv 1 962.0000 3
57 another 2 638.0000 1
134 another 2 858.0000 2
62 another 2 548.0000 3
98 xzcvzxc 3 863.0000 1
106 xzcvzxc 3 634.0000 2
98 xzcvzxc 3 1168.0000 3
我在想,如果一个有是一种方法来收集product_id在群组之前,并将它们添加到一个字段中,也许逗号分开
78,55,66 sdzvzcxv 1 4047.0000 1
143,77,88 sdzvzcxv 1 628.0000 2
59,77,88 sdzvzcxv 1 962.0000 3
57,77,88 another 2 638.0000 1
134,77,88 another 2 858.0000 2
62,77,88 another 2 548.0000 3
98,77,890 xzcvzxc 3 863.0000 1
106,76,88 xzcvzxc 3 634.0000 2
98,57,87 xzcvzxc 3 1168.0000 3
您是否问我们**一次为您做好一件事? http://stackoverflow.com/questions/6363028/group-by-with-adding-the-values – 2011-06-15 20:01:39
我不是要求任何人做我的工作......第一个问题已得到解决,我正在寻求帮助,甚至有可能.. – Trace 2011-06-15 20:05:39