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我有复杂的查询，效果很好（MS SQL 2012）。但总结相同的价格项目时会出现错误。它对它们进行了正确的计数，但只需要花费一次，而不是将它们作为计数。只有当相同的商品具有相同的价格并来自同一国家时才会出现。这是我的问题;Dynamic Pivot中总计错误值
CREATE TABLE #ITEMS(ID INT,NAME VARCHAR(30))
INSERT INTO #ITEMS
SELECT 1, 'laptop'
UNION ALL
SELECT 2, 'phone'
UNION ALL
SELECT 3, 'playstation'
UNION ALL
SELECT 4, 'MacBook'
CREATE TABLE #Country(ID INT,NAME VARCHAR(30))
INSERT INTO #Country
SELECT 1, 'England'
UNION ALL
SELECT 2, 'Sweden'
UNION ALL
SELECT 3, 'Russia'
UNION ALL
SELECT 4, 'Italy'
CREATE TABLE [#Pre-Request](Id INT, countryId INT, ItemId INT)
INSERT INTO [#Pre-Request]
SELECT 1,1,3
UNION ALL
SELECT 2,2,1
UNION ALL
SELECT 3,2,2
UNION ALL
SELECT 4,3,3
UNION ALL
SELECT 5,3,3
UNION ALL
SELECT 6,2,3
CREATE TABLE #Offers(Id INT, PRICE VARCHAR(50))
INSERT INTO #Offers
SELECT 18,'257$'
UNION ALL
SELECT 19,'151$'
UNION ALL
SELECT 20,'424$'
UNION ALL
SELECT 21,'433$'
UNION ALL
SELECT 22,'151$'
CREATE TABLE #Request(Id INT, preReqId INT, requestStatus INT,winOfferId INT)
INSERT INTO #Request
SELECT 44, 1, 3, 18
UNION ALL
SELECT 11, 2, 4, 21
UNION ALL
SELECT 53, 3, 4, 20
UNION ALL
SELECT 87, 4, 3, 22
UNION ALL
SELECT 43, 5, 3, 19
UNION ALL
SELECT 43, 6, 2, Null
;WITH CTE AS
(
SELECT DISTINCT I.NAME ITEMNAME,C.NAME COUNTRYNAME
,CAST(REPLACE(TAB.PRICE,'$','')AS INT)PRICE
,COUNT(CASE WHEN TAB.PRICE IS NOT NULL THEN I.NAME END) OVER(PARTITION BY C.NAME,I.NAME) CNTITEM
FROM [#Pre-Request] PR
LEFT JOIN #Items I ON PR.ITEMID=I.ID
LEFT JOIN #COUNTRY C ON PR.COUNTRYID = C.ID
OUTER APPLY
(
SELECT R.preReqId,R.winOfferId,O.PRICE
FROM #Request R
JOIN #Offers O ON R.winOfferId=O.Id
WHERE PR.ID=R.preReqId
)TAB
UNION
-- Used to select Item name and country that are not in Pre-request table and other tables
SELECT I.NAME ,C.NAME ,NULL,0
FROM #Items I
CROSS JOIN #COUNTRY C
)
,CTE2 AS
(
-- Find the sum for number of items
SELECT DISTINCT ISNULL(ITEMNAME,'TOTAL')ITEMNAME,ISNULL(COUNTRYNAME,'TOTAL')COUNTRYNAME,
SUM(PRICE)PRICE
FROM CTE
GROUP BY ITEMNAME,COUNTRYNAME
WITH CUBE
)
,CTE3 AS
(
-- Find the sum of PRICE
SELECT DISTINCT ISNULL(ITEMNAME,'TOTAL')ITEMNAME,ISNULL(COUNTRYNAME,'TOTAL')COUNTRYNAME--,CNTITEM
,SUM(CNTITEM)CNTITEM
FROM
(
SELECT DISTINCT ITEMNAME,COUNTRYNAME,CNTITEM
FROM CTE
)TAB
GROUP BY ITEMNAME,COUNTRYNAME
WITH CUBE
)
SELECT C2.*,C3.CNTITEM,
CAST(C3.CNTITEM AS VARCHAR(20))+'x'+' ' + CAST(C2.PRICE AS VARCHAR(20))+'$' NEWCOL
INTO #NEWTABLE
FROM CTE2 C2
JOIN CTE3 C3 ON C2.COUNTRYNAME=C3.COUNTRYNAME AND C2.ITEMNAME=C3.ITEMNAME
DECLARE @cols NVARCHAR (MAX)
SELECT @cols = COALESCE (@cols + ',[' + ITEMNAME + ']', '[' + ITEMNAME + ']')
FROM (SELECT DISTINCT ITEMNAME FROM #NEWTABLE WHERE ITEMNAME<>'TOTAL') PV
ORDER BY ITEMNAME
-- Since we need Total in last column, we append it at last
SELECT @cols += ',[Total]'
DECLARE @query NVARCHAR(MAX)
SET @query = 'SELECT COUNTRYNAME,' + @cols + ' FROM
(
SELECT DISTINCT ITEMNAME,COUNTRYNAME,ISNULL(NEWCOL,''0x 0$'')NEWCOL
FROM #NEWTABLE
) x
PIVOT
(
MIN(NEWCOL)
FOR ITEMNAME IN (' + @cols + ')
) p
ORDER BY CASE WHEN (COUNTRYNAME=''Total'') THEN 1 ELSE 0 END,COUNTRYNAME'
EXEC SP_EXECUTESQL @query
这里是结果;
正如你可以看到有2个“游戏站”，从“俄罗斯”，就需要正确的次数（2次），但只取1价“151 $”（通常它必须是302 $）。我怎样才能解决这个问题，而不是从查询做重大更改？谢谢。
我检查快速查询，我认为问题在于转轴之前。如果对我来说违反直觉，第二个存储在项目x总价格的一个列号中。当我看到'2x 302'时，我想象每个302 $ 2个项目，总成本302个项目不能包含2个项目，您不能将每个产品和总数的项目编号/价格总和分成两列分开列吗？ – lad2025
您正在使用哪个版本的SQL Server？ – jpw
@jpw MS SQL 2012 – TeknobilSoft