我想建立一个程序,它总结了一个大整数C. 所以我准备好了代码。程序编译通过mingw和Visual C++编译器成功传递。但是我的运行部分有问题。奇怪的是,当我在Visual Studio中调试程序时没有问题,但是当我运行它时,Windows显示程序停止工作。 这是代码:C str功能和malloc
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <math.h>
#include <ctype.h>
#include "sum.h"
int isNumber(char* number)
{
int lenght = strlen(number);
int i,result = 0;
for (i = 0 ; i < lenght ; i++)
{
if (isdigit(*number++))
{
result = 1;
}
else
{
result = 0;
break;
}
}
return result;
}
int cti(char ch)
{
return ch - '0';
}
char* addZeros(char* number,int lenght)
{
int num_lenght = strlen(number),size = abs(lenght - num_lenght),i;
char* zeros = (char*)malloc(size);
strcpy(zeros,"");
zeros[size - 1] = '\0';
for (i = 0 ; i < abs(lenght - num_lenght) ; i++)
{
strcpy(&zeros[i],"0");
}
strncat(zeros,number,size);
number = (char*)malloc(sizeof(char)*size);
strncpy(number,zeros,size);
return number;
}
char* sum(char* numberOne,char* numberTwo)
{
if (numberOne == NULL || numberTwo == NULL)
return NULL;
if (!isNumber(numberOne) || !isNumber(numberTwo))
return NULL;
int CF = 0;
int lenghtOne = strlen(numberOne),lenghtTwo = strlen(numberTwo);
if (lenghtOne == 0 || lenghtTwo == 0)
return lenghtOne == 0 ? numberTwo : numberOne;
int max = lenghtOne > lenghtTwo? lenghtOne : lenghtTwo,index;
char* result = (char*)malloc(max);
int res = 0;
result[max] = '\0';
if (lenghtOne > lenghtTwo) numberTwo=addZeros(numberTwo,strlen(numberOne));
else if (lenghtOne < lenghtTwo) numberOne = addZeros(numberOne,strlen(numberTwo));
for (index = max - 1 ; index >=0 ; index--)
{
res = cti(numberOne[index]) + cti(numberTwo[index]);
if (((res%10) + CF) > 9)
{
int num = ((res%10) + CF);
result[index] = (char)((int)'0'+num%10);
CF = num/10;
}
else
{
result[index] = (char)((int)'0'+((res%10) + CF));
CF = res/10;
}
}
return result;
}
int main(int argc, char *argv[])
{
char* num = "12345678";
char* num2= "2341";
char* result = sum(num,num2);
printf("%s\n",result);
return 0;
}
我认为这个问题是在某处的指针,但我没有绝对的把握这一点。谁能帮我?
那么是什么问题,你看,当你看到了吗? – johannes