2015-03-31 58 views
0

下面的脚本抛出我这个错误:无效的参数号SQLSTATE [HY093]:没有定义的参数

SQLSTATE[HY093]: Invalid parameter number: parameter was not defined

错误来自这些行:

$query .= "WHERE username1=:un1"; 
$binValues["un1"] = $_POST['username1']; 

是否有与PHP的任何问题句法?

我完整的脚本:

<?php 

    require_once "config.inc.php"; 

    $query = "UPDATE customer SET "; 
    $binValues = []; 


    if(!empty($_POST['eidosmetaf1'])) { 
     $query .= "eidosmetaf1 = :e1"; 
     $binValues["e1"] = $_POST['eidosmetaf1']; 
    } 

    if(!empty($_POST['weight1'])) { 
     $query .= ",weight1 = :w1"; 
     $binValues["w1"] = $_POST['weight1']; 
    } 

    if(!empty($_POST['startNomos1'])){ 
     $query .= ",startNomos1 = :sn1"; 
     $binValues["sn1"] = $_POST['startNomos1']; 
    } 

    if(!empty($_POST['startPoli1'])) { 
     $query .= ",startPoli1 = :sc1"; 
     $binValues["sc1"] = $_POST['startPoli1']; 
    } 

    if(!empty($_POST['start_lat'])) { 
     $query .= ",start_lat = :slat1"; 
     $binValues["slat1"] = $_POST['start_lat']; 
    } 

    if(!empty($_POST['start_lng'])) { 
     $query .= ",start_lng = :slng1"; 
     $binValues["slng1"] = $_POST['start_lng']; 
    } 

    if(!empty($_POST['finalNomos1'])) { 
     $query .= ",finalNomos1 = :fn1"; 
     $binValues["fn1"] = $_POST['finalNomos1']; 
    } 

    if(!empty($_POST['finalPoli1'])) { 
     $query .= ",finalPoli1 = :fc1"; 
     $binValues["fc1"] = $_POST['finalPoli1']; 
    } 

    if(!empty($_POST['final_lat'])) { 
     $query .= ",final_lat = :flat1"; 
     $binValues["flat1"] = $_POST['final_lat']; 
    } 

    if(!empty($_POST['final_lng'])) { 
     $query .= ",final_lng = :flng1"; 
     $binValues["flng1"] = $_POST['final_lng']; 
    } 

    if(!empty($_POST['depDate1'])) { 
     $query .= ",depDate1 = :dD1"; 
     $binValues["dD1"] = $_POST['depDate1']; 
    } 

    if(!empty($_POST['depTime1'])) { 
     $query .= ",depTime1 = :dT1"; 
     $binValues["dT1"] = $_POST['depTime1']; 
    } 

    if(!empty($_POST['specialservices1'])) { 
     $query .= ",specialservices1 = :ex1"; 
     $binValues["ex1"] = $_POST['specialservices1']; 
    } 

    if(!empty($_POST['comments1'])) { 
     $query .= ",comments1 = :c1"; 
     $binValues["c1"] = $_POST['comments1']; 
     } 

     //error here 
     $query .= "WHERE username1=:un1"; 
     $binValues["un1"] = $_POST['username1'];  


     $query .= "and comments1=:c1_old"; 
     $binValues["c1_old"] = $_POST['comments2_old']; 


    try { 
     $stmt = $db->prepare($query); 
     $stmt->execute($binValues); 

    } catch (PDOException $ex) { 
     $response["success"] = 0; 
     $response["message"] = "Database Error2. Please Try Again!"; 
     echo $ex->getMessage(); 
     die(json_encode($response)); 
    }  

    $response["success"] = 1; 
    $response["message"] = "..............!"; 
    echo json_encode($response); 


?> 
+0

类似的问题:http://stackoverflow.com/q/29354264/3933332你不觉得? – Rizier123 2015-03-31 12:24:18

+0

* Hm ... *您可能需要在'where' ---'$ query。=“WHERE username1 =:un1”之前留出空格;' – 2015-03-31 12:26:37

+1

您好,Rizier,您是否永远在线;哈哈哈。但我坚持:现在在特定的路线上是什么问题; – johnnal 2015-03-31 12:27:16

回答

1

正如我已经解决了以前的代码,我会建议你从我的答案使用代码:https://stackoverflow.com/a/29354781/3933332因为它是一个简单得多阅读和理解。

而且如果你用我的代码,你可以添加你WHERE条款是这样的:

<?php 

    //... 

    foreach($checkedValues as $k => $v) { 
     $query .= "$v = :$k,"; 
     $bindValues[$k] = $_POST[$v]; 
    } 

    $query = rtrim($query, ","); 

    //fixed code here 
    if(isset($_POST['username1'])) { 
     $query .= " WHERE username1=:un1"; 
     $bindValues["un1"] = $_POST["username1"]; 
    } 

    if(isset($_POST['comments1'])) { 
     $query .= " AND comments1=:c1_old"; 
     $bindValues["c1_old"] = $_POST["comments1"]; 
    } 


    try {   
     $stmt = $db->prepare($query); 
     $stmt->execute($binValues);   
    } catch (PDOException $ex) { 
     $response["success"] = 0; 
     $response["message"] = "Database Error2. Please Try Again!"; 
     echo $ex->getMessage(); 
     die(json_encode($response)); 
    }  

    //... 

?> 
+0

但我想我复制 - 粘贴你的代码..在你更新之前 – johnnal 2015-03-31 12:45:27

+0

@johnnal然后回到我的最后一个答案,看看我的更新代码:D然后,你也可以在这里结合新代码。 – Rizier123 2015-03-31 12:53:17

+0

好的,我会的。但问题依然存在:为什么我提供的特定代码是错误的; – johnnal 2015-03-31 12:56:04

-1
$binValues[":un1"] = $_POST['username1'] 
+0

添加:不起作用。请注意,例如“$ binValues [”dD1“] = $ _POST ['depDate1'];”正在工作完美 – johnnal 2015-03-31 12:39:10

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