pygame中的贪吃蛇游戏：身体发育函数

Question

我正在pygame中编写蛇，但我对如何实现蛇的增长功能没有一个非常清晰的想法。我制作了一个包含头部坐标（大约30x30像素）的列表（“lista_cobra”），并考虑制作另一个列表，其中包含头部的最后位置，不包括最后一个部分，因此绘制身体蛇（“corpito”也是30x30像素），从那里积累每一点。这个想法在实践中并不奏效，因为我认为身体不能做出蛇的特征性运动。我的问题是如何在保持身体特征性运动的同时从头部的前一个坐标增长身体？

#-*- coding: latin1 -*- 

import pygame, sys, os, random, math, time 
from pygame.locals import * 

pygame.init() 

##### Cores ###### 
preto = (0, 0, 0) 
vermelho = (255, 0, 0) 
################## 

################## 

dimensao = [800, 600] 
tela = pygame.display.set_mode(dimensao) 

######### Objetos ########### 

gramado = pygame.image.load(os.path.join("images", "fundocobrinha.jpg")) 
paredes = pygame.image.load(os.path.join("images", "paredes.png")) 
comp = pygame.image.load(os.path.join("images", "comidacobra.png")) 
comp = pygame.transform.scale(comp, (18, 20)) 
cabeca = pygame.image.load(os.path.join("images", "cabecadacobra.png")) 
corpito = pygame.image.load(os.path.join("images", "corpodacobra.png")) 
corpo = pygame.transform.rotate(cabeca, 0) 
caminhodafonte = os.path.join("fonte", "lunchds.ttf") 
fonte = pygame.font.Font(caminhodafonte, 22) 
fonte_fim = pygame.font.Font(caminhodafonte, 25) 

############################# 

###### Distancia ######### 

def distancia(x, y, x2, y2): 
    distancia = math.sqrt(((x2 - x) ** 2) + ((y2 - y) ** 2)) 
    return distancia 

########################## 

########### cobra ############# 

pontos = 0 
vidas = 3 
raio_cobra = 12 
raio_corpo = 12 
x = [130] 
y = [130] 

def cobrinha(): 
    global x, y, corpo, direcao, x_modificado, y_modificado 

    tela.blit(corpo, (x[0] - raio_cobra, y[0] - raio_cobra)) 

    if direcao == "direita": 
     corpo = pygame.transform.rotate(cabeca, 0) 
     x_modificado = 3 
     y_modificado = 0 
    elif direcao == "esquerda": 
     corpo = pygame.transform.rotate(cabeca, 180) 
     x_modificado = -3 
     y_modificado = 0 
    elif direcao == "cima": 
     corpo = pygame.transform.rotate(cabeca, 90) 
     y_modificado = -3 
     x_modificado = 0 
    elif direcao == "baixo": 
     corpo = pygame.transform.rotate(cabeca, 270) 
     y_modificado = 3 
     x_modificado = 0 

    x[0] += x_modificado 
    y[0] += y_modificado 

################################ 

###### Comida da Cobra ######### 

raio_cCobra = 4 
nova_comida = True 
x2 = 0 
y2 = 0 

def comida(): 
    global x2, y2, comp, nova_comida 
    if nova_comida: 
     x2 = random.randint(47, 747) 
     y2 = random.randint(56, 548) 
     nova_comida = False 
    tela.blit(comp, (x2 - raio_cCobra, y2 - raio_cCobra)) 

################################ 

########## Informações de status ############# 

def status_de_jogo(): 
    global pontos, fonte 
    p = fonte.render("Pontos: " + str(pontos), True, preto) 
    tela.blit(p, (45,37)) 
    v = fonte.render("Vidas :" + str(vidas), True, preto) 
    tela.blit(v, (45,61)) 

############################### 

######## mensagen de tela ###### 

def mensagem_de_tela(): 
    mensagem_de_texto = fonte_fim.render("Fim de Jogo, pressione C para jogar ou Q para sair.", True, vermelho) 
    tela.blit(mensagem_de_texto,[55,200]) 

################################ 

######################################## Loop principal ################################################### 

def loop_jogo(): 
    global x, y, x2, x2, vidas, pontos, distancia, corpo, raio_cCobra, raio_cobra, counter, nova_comida, lista_cobra,lista_corpo, direcao 

    direcao = "direita" 

    lista_cobra = [] 

    clock = pygame.time.Clock() 

    sair_do_jogo = False 
    fim_de_jogo = False 

    while not sair_do_jogo: 

     while fim_de_jogo == True: 
      mensagem_de_tela() 
      pygame.display.update() 
      for event in pygame.event.get(): 
       if event.type == pygame.KEYDOWN: 
        if event.key == pygame.K_q: 
         sair_do_jogo = True 
         fim_de_jogo = False 
        if event.key == pygame.K_c: 
         loop_jogo() 

     #### Capturando todos os eventos durante a execução #### 
     for event in pygame.event.get(): 
      if event.type == pygame.KEYDOWN: 
       if event.key == pygame.K_RIGHT: 
        direcao = "direita" 

       elif event.key == pygame.K_LEFT: 
        direcao = "esquerda" 

       elif event.key == pygame.K_UP: 
        direcao = "cima" 

       elif event.key == pygame.K_DOWN: 
        direcao = "baixo" 

      if event.type == QUIT: 
       sair_do_jogo = True 

     ####### posição da cabeça da cobra ########### 

     cabeca_cobra = [] 
     cabeca_cobra.append(x[0]) 
     cabeca_cobra.append(y[0]) 
     lista_cobra.append(cabeca_cobra) 

     tela.blit(gramado, (0, 0)) 
     tela.blit(paredes, (0, 0)) 

     comida() 
     cobrinha() 
     status_de_jogo() 

     clock.tick(60) 

     fps = clock.get_fps() 

     pygame.display.set_caption("Shazam Caraí II ## FPS: %.2f" %fps) 

     ########## Se bater nas paredes ################## 
     if (x[0] >= 751 or x[0] <= 44) or (y[0] >= 553 or y[0] <= 42): 

      vidas -= 1 
      x = 400 
      y = 300 

     ################################################## 

     if distancia(int(x[0]), int(y[0]), x2, y2) < (raio_cobra + raio_cCobra): 

      nova_comida = True 
      pontos += 1 

     if vidas == 0: 

      fim_de_jogo = True 
      mensagem_de_tela() 

     pygame.display.flip() 
########################################################################################################### 

loop_jogo() 

Answer 1

我看不懂你的来源，但我会试试看。

蛇的尸体由lista_cobra中的位置组成。将蛇的长度存储在变量len_cobra中。现在，当头部移动时，磁头的新位置具有在lista_cobra顶部加入：

lista_cobra.insert(0, head_cobra) 

不过这个名单现在必须再次截断为眼镜蛇的长度

lista_cobra = lista_cobra[:len_cobra] 

现在回到你的问题：如何种植蛇？通过每次发生特定事件时（通常在一些移动之后）将len_cobra增加1，很容易完成。其余的已经被照顾了。