SQL得到所有匹配的要求，即

Question

嘿所有我想知道我怎么会从表中得到的所有查询，只得到第一个和停止

我的代码查询：

   $result1 = mysql_query("SELECT `to` FROM transactions WHERE `from` = '$user'"); 

       $row = mysql_fetch_row($result1); 

       $result2 = mysql_query("SELECT `amount` FROM transactions WHERE `from` = '$user'"); 

       $row2 = mysql_fetch_row($result2); 


       echo "<li>TO</li>"; 
       echo "<li>AMOUNT</li>"; 
       echo "<li>$row[0]</li>"; 
       echo "<li>$row2[0]</li>"; 
       echo "<li>$row[1]</li>"; 
       echo "<li>$row2[1]</li>"; 
       echo "<li>$row[2]</li>"; 
       echo "<li>$row2[2]</li>"; 
       echo "<li>$row[3]</li>"; 
       echo "<li>$row2[4]</li>"; 
       echo "<li>$row[4]</li>"; 
       echo "<li>$row2[5]</li>"; 

我数据库：

Answer 1

$row = mysql_fetch_row($result1); will only fetch one row 

您需要使用while

$query = mysql_query("SELECT `to`, `amount` FROM transactions WHERE `from` = '$user'"); 
echo "<li>TO</li>"; 
echo "<li>AMOUNT</li>"; 
while ($row = mysql_fetch_assoc($query)) { 

    echo "<li>{$row['to']}</li>"; 
    echo "<li>{$row['amount']}</li>"; 
}