我想在codeigniter 2.2中执行此查询。我阅读文档http://www.codeigniter.com/user_guide/database/results.html。Codeigniter加入查询失败
我的控制器代码是这样的
$query = $this->db->query("SELECT a.id, a.child, a.immune, a.immun_date, b.id, b.fname, b.lname, c.id, c.name
FROM immun a, children b, immun_master c
WHERE a.child = b.id
AND c.id = a.immune
");
$immun = array();
foreach ($query->result()as $row) {
$immun[] = array(
$row->id,
$row->child,
$row->immune,
$row->immun_date,
);
}
已打开,结果是这样的:
array (
0 =>
array (
0 => '2',
1 => '1001',
2 => '2',
3 => '2011-04-23',
),
1 =>
array (
0 => '3',
1 => '1001',
2 => '3',
3 => '2011-04-30',
),
2 =>
array (
0 => '6',
1 => '1002',
2 => '6',
3 => '2011-04-30',
),
3 =>
array (
0 => '5',
1 => '1002',
2 => '5',
3 => '2011-04-29',
),
4 =>
array (
0 => '1',
1 => '1003',
2 => '1',
3 => '2011-01-06',
),
5 =>
array (
0 => '3',
1 => '1005',
2 => '3',
3 => '2010-10-04',
),
6 =>
array (
0 => '3',
1 => '1231',
2 => '3',
3 => '2014-08-01',
),
)
这些都是错误的结果。我期待的是查询的合并结果。下面是我所得到的,当我在phpMyAdmin运行查询现在
id child immune immun_date id fname lname id name
1 1001 2 2011-04-23 1001 Johny Jame 2 Swine Flu Vaccine
2 1001 3 2011-04-30 1001 Johny Jame 3 Bird Flu Vaccine
3 1002 6 2011-04-30 1002 Chelsea James 6 Hepatitis B
4 1002 5 2011-04-29 1002 Chelsea James 5 Measles Vaccine
5 1003 1 2011-01-06 1003 Charles Jacob 1 H1N1 Vaccine
6 1005 3 2010-10-04 1005 Hansome Little 3 Bird Flu Vaccine
7 1231 3 2014-08-01 1231 Jennifer Ylanan 3 Bird Flu Vaccine
,这将是很好,如果我能得到CI回到同一组合并的数据。我可以看到,它只是返回表格查询进行免疫,而CI没有从另一个表中加入数据。我在某处读到CI没有被构建来处理复杂的查询?真的吗?
任何想法如何获得我需要的数据? 谢谢!
结果是预期的,因为你在做交叉连接。 – 2015-02-11 17:21:15
感谢您的线索! – user1794918 2015-02-11 18:44:55