2017-07-06 52 views
0

中给出我在将XAMPP 5.6升级到XAMPP 7.2后对PHP代码的结果有问题。在我的MacPro中。 什么是修正PHP脚本中的代码的调整?因为他们给了我一个警告:Affiliate升级XAMPP 5.6到XAMPP 7.2,我有 - >警告:mysqli_num_rows()期望参数1是mysqli_result,布尔在

警告:mysqli_num_rows()预计参数1被mysqli_result, 布尔在...

感谢您的帮助说明。

我的代码:?

<?php 

include ("../inc/link.php"); 

    $alert = "none"; 

    if(isset($_POST["btn-login"])) { 
    //echo "Run Action Of Form Login"; 

    //echo $_POST["username"]; 
    //echo $_POST["password"]; 

    $username = $_POST["username"]; 
    $password = $_POST["password"]; 
    $query   = mysqli_query($conex,"SELECT * FROM table_admin WHERE adm_name='".$username."' AND adm_password='".md5($password)."' "); 
    $count   = mysqli_num_rows($query); 

    echo  $count; 

} 

>

+0

检查'mysqli_error($ CONEX)'任何线索 – apokryfos

回答

0
<?php 

$conex = mysqli_connect("localhost","root","","javamartDB") or die ("Can not connect to the database"); 

    $alert = "none"; 

    if(isset($_POST["btn-login"])) { 
    //echo "Run Action Of Form Login"; 

    //echo $_POST["username"]; 
    //echo $_POST["password"]; 

    $username = $_POST["username"]; 
    $password = $_POST["password"]; 
    $query  = mysqli_query($conex,"SELECT * FROM table_admin "); 
    $count  = mysqli_num_rows($query); 
if(mysqli_num_rows($count)>0){ 
while($row= mysqli_fetch_row($query)); 
     print_r($row[0],$row[1]); 
     die; 
} 

} 

?> 
+0

请检查这个答案,让我知道,如果任何问题 – sanjay

+0

非常感谢桑杰...高度赞赏。但是,他们更超过警告,就像这样: 警告:mysqli_num_rows()预计参数1被mysqli_result,布尔在/Applications/XAMPP/xamppfiles/htdocs/javamart/admin/login.php给出线12 警告: mysqli_num_rows()期望参数1是mysqli_result,null在第13行的/Applications/XAMPP/xamppfiles/htdocs/javamart/admin/login.php中给出 – Theodore

+0

我对变量$ row和$ res有怀疑吗? – Theodore

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