警告：mysqli_fetch_array（）预计参数1被mysqli_result，布尔在

Question

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如何修复mysqli_fetch_array（）预计参数1被mysqli_result，布尔让步......

错误行：而（$ LVL = mysqli_fetch_array （$ lvls））

$result = mysqli_query($conn, "SELECT count(*) FROM players"); 
$roww = mysqli_fetch_row($result); 
$total = $roww[0]; 
$playersCount = mysqli_fetch_row($result); 
$pagesCount = ceil($playersCount/$playersOnPage); 
$fromLimit = ($currentPage - 1) * $playersOnPage; 
$dbquery = "SELECT * FROM `players` ORDER BY `score` DESC".$fromLimit.", ".$playersOnPage.""; 
$lvls = mysqli_query($conn, $dbquery, MYSQLI_USE_RESULT); 

while($lvl = mysqli_fetch_array($lvls)) 

Answer 1

尝试使用下面的代码：

$result = mysqli_query($conn, "SELECT count(*) FROM players"); 
$roww = mysqli_fetch_row($result); 
$total = $roww[0]; 
$playersCount = mysqli_fetch_row($result); 
$pagesCount = ceil($playersCount/$playersOnPage); 
$fromLimit = ($currentPage - 1) * $playersOnPage; 

//Here was the mistake! 
$dbquery = "SELECT * FROM `players` ORDER BY `score` DESC LIMIT ".$fromLimit.", ".$playersOnPage; 
$lvls = mysqli_query($conn, $dbquery, MYSQLI_USE_RESULT); 

while($lvl = mysqli_fetch_array($lvls)) 

说明：

的$dbquery的结果看起来就会像下面这样：

SELECT * FROM `players` ORDER BY `score` DESC1, 2 -- not valid! 

从我的解决方案新$dbquery上面你会得到如下：

SELECT * FROM `players` ORDER BY `score` DESC LIMIT 1, 2 -- valid