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我希望有人能帮助大家尖叫!声明中的循环问题
基本上我试图用下面的语句做一些事情;
首先,我想检查用户标识是否存在于member_categories_position中。 如果是我想然后排除第二个语句中的所有条目,其中member_id等于第一条语句的所有结果 第三个语句是else语句,如果member_id不存在于member_categories位置中,则显示else语句。
问题 - 第一个系统的结果很好,但是当我尝试插入第二个语句(!='$ memid')时,没有产生任何结果,也没有任何效果。我认为问题是$ memid是一个循环结果。
如何获得第二个声明,说member_categories_position中的任何member_id都不会在该声明中显示?
$sql2 = "
SELECT *
FROM member_categories_position a
JOIN member_users b
ON b.id = a.member_id";
$rs2 = mysql_query($sql2);
while ($row = mysql_fetch_array($rs2))
{
$memid = "".$row['member_id']."";
}
if(mysql_num_rows($rs2) != 0)
{
$new= "
SELECT *
FROM member_categories
JOIN member_users
ON member_categories.member_id=member_users.id
JOIN member_config
ON member_categories.member_id=member_config.member_id
WHERE
member_categories.categories='$category'
AND member_categories.member_id !='$field'
GROUP BY member_config.member_id
ORDER BY RAND() limit 0,42";
$rs = mysql_query($new);
while ($row = mysql_fetch_assoc($rs))
{
echo "result excluding member ids from the first statement";
}
echo "<div class=\"clear\"></div>";
}
else
{
$new= "
SELECT *
FROM member_categories
JOIN member_users
ON member_categories.member_id=member_users.id
JOIN member_config
ON member_categories.member_id=member_config.member_id
WHERE
member_categories.categories='$category'
GROUP BY member_config.member_id
ORDER BY RAND() limit 0,42";
$rs = mysql_query($new);
while ($row = mysql_fetch_assoc($rs))
{
echo "Result with all member ids";
}
echo "<div class=\"clear\"></div>";
} } <-- (second is a stray from original post)
请编辑您上面的代码使用正确的缩进 - 它会让你更容易让我们来帮助你。 – jball 2010-12-02 16:52:55
$ field和$ category从哪里得到它们的值? – 2010-12-02 17:07:20